Answer:
![\omega_f = 585.37 \ rev/s](https://tex.z-dn.net/?f=%5Comega_f%20%3D%20585.37%20%5C%20rev%2Fs)
Explanation:
given,
mass of wheel(M) = 3 Kg
radius(r) = 35 cm
revolution (ω_i)= 800 rev/s
mass (m)= 1.1 Kg
I_{wheel} = Mr²
when mass attached at the edge
I' = Mr² + mr²
using conservation of angular momentum
![I \omega_i = I' \omega_f](https://tex.z-dn.net/?f=I%20%5Comega_i%20%3D%20I%27%20%5Comega_f)
![(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f](https://tex.z-dn.net/?f=%20%28Mr%5E2%29%20%5Ctimes%20800%20%3D%20%28%20M%20r%5E2%20%2B%20m%20r%5E2%29%20%5Comega_f)
![M\times 800 = ( M + m )\omega_f](https://tex.z-dn.net/?f=%20M%5Ctimes%20800%20%3D%20%28%20M%20%2B%20m%20%29%5Comega_f)
![3\times 800 = (3+1.1)\times \omega_f](https://tex.z-dn.net/?f=%203%5Ctimes%20800%20%3D%20%283%2B1.1%29%5Ctimes%20%5Comega_f)
![2400 = (4.1)\times \omega_f](https://tex.z-dn.net/?f=%202400%20%3D%20%284.1%29%5Ctimes%20%5Comega_f)
![\omega_f = 585.37 \ rev/s](https://tex.z-dn.net/?f=%5Comega_f%20%3D%20585.37%20%5C%20rev%2Fs)
Answer: Move the small car so it appears on the left side of the lens.
Explanation:
Because the lens is reflective the small car would apear on the same side as the normal car.
Hope this helps :)
Answer:
A step by step to walk
Explanation:
One- Make sure your shoes are tied so that you dont trip
Two- Make sure your way is a cleared path so you dont fall or even hurt yourself
three- use both set of lets to go in any direction you want.
Four- when walking make sure to try and keep a steedy pace so that both set of legs are going up and down but in harmony
The quantity work has to do with a force causing a displacement. Work has nothing to do with the amount of time that this force acts to cause the displacement. Sometimes, the work is done very quickly and other times the work is done rather slowly. For example, a rock climber takes an abnormally long time to elevate her body up a few meters along the side of a cliff. On the other hand, a trail hiker (who selects the easier path up the mountain) might elevate her body a few meters in a short amount of time. The two people might do the same amount of work, yet the hiker does the work in considerably less time than the rock climber. The quantity that has to do with the rate at which a certain amount of work is done is known as the power. The hiker has a greater power rating than the rock climber.
Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation.
Power = Work / time
or
P = W / t
The kinetic energy of the object is 392 Joules.