1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zina [86]
3 years ago
6

I have to build a roller coaster with 3 hills and 2 valleys. Hill A is 15 inches high, valley B is 3 inches high, hill C is 8 in

ches high, valley D is 5 inches high and the last hill E is 3 inches high. My questions are, when using a tennis ball as the cart.
1. What is the initial velocity of the tennis ball at the moment of its release at the top of the track? Use this insight to calculate the initial and potential kinetic energy.
2. Calculate the amount of gravitational potential energy at the top of each hill and at the bottom of each valley. Be sure to convert your distance measurements to meters. Use and approximate value of 58.0g. for the mass of the tennis ball, and 9.81 m/s squared as the excelleration due to gravity.
3. Suppose that the force due to friction is negligible. What can you say about the total energy of the tennis ball? Continue to assume that the force due to friction is negligible. Use the information you've gathered to calculate the kinetic energy and the total energy at each location. Describe the relationship between the potential and kinetic energy of the tennis ball as it travels the length of the roller coaster.
4. Compare your answer to the previous question with your observations In conducting this experiment. Discuss weather energy was conserved in your experiment. Was friction negligible?
Physics
2 answers:
rusak2 [61]3 years ago
7 0

1. What is the initial velocity of the tennis ball at the moment of its release at the top of the track? Use this insight to calculate the initial and potential kinetic energy.

Answer:

v_i = 0 m/s

Explanation:

As initially it starts from hill A so its initial KE = 0 so initial speed is also zero

Also its initial potential energy is given as

U_i = mgh_1

here we know

h_1 = 15 inch

2. Calculate the amount of gravitational potential energy at the top of each hill and at the bottom of each valley. Be sure to convert your distance measurements to meters. Use and approximate value of 58.0 g. for the mass of the tennis ball, and 9.81 m/s squared as the acceleration due to gravity.

Answer:

U_1 = 0.058(9.81)(0.381) = 0.22 J

U_2 = 0.058(9.81)(0.0762) = 0.043 J

U_3 = 0.058(9.81)(0.203) = 0.12 J

U_4 = 0.058(9.81)(0.127) = 0.072 J

U_5 = 0.058(9.81)(0.0762) = 0.043 J

Explanation:

As we know that gravitational potential energy is given as

U_i = mgh

here we know for hill A

h_1 = 15 inch = 0.381 m

U_1 = 0.058(9.81)(0.381) = 0.22 J

For Valley B

h_2 = 3 inch = 0.0762 m

U_2 = 0.058(9.81)(0.0762) = 0.043 J

For Hill C

h_3 = 8 inch = 0.203 m

U_3 = 0.058(9.81)(0.203) = 0.12 J

For valley D

h_4 = 5 inch = 0.127 m

U_4 = 0.058(9.81)(0.127) = 0.072 J

For Hill E

h_5 = 3 inch = 0.0762 m

U_5 = 0.058(9.81)(0.0762) = 0.043 J

3. Suppose that the force due to friction is negligible. What can you say about the total energy of the tennis ball? Continue to assume that the force due to friction is negligible. Use the information you've gathered to calculate the kinetic energy and the total energy at each location. Describe the relationship between the potential and kinetic energy of the tennis ball as it travels the length of the roller coaster.

Answer:

KE_1 = 0 J

KE_2 = 0.177 J

KE_3 = 0.10 J

KE_4 = 0.148 J

KE_5 = 0.177 J

Explanation:

Total energy will remain conserved in all cases as friction is not here

so here we will say

Total energy is 0.22 J

now kinetic energy as Hill A

KE_1 = 0

kinetic energy at Valley B

KE_2 = 0.22 - 0.043 = 0.177 J

kinetic energy at Hill C

KE_3 = 0.22 - 0.12 = 0.1 J

Kinetic energy At Valley D

KE_4 = 0.22 - 0.072 = 0.148 J

Kinetic energy at Hill E

KE_5 = 0.22 - 0.043 = 0.177 J

4. Compare your answer to the previous question with your observations In conducting this experiment. Discuss weather energy was conserved in your experiment. Was friction negligible?

ANSWER

In actual experiment if the friction force is negligible then in that case the final kinetic energy at each case is nearly same but if the friction is not negligible then in that case the final kinetic energy will not be same as we calculated above due to energy loss in friction.

pickupchik [31]3 years ago
3 0
I am doing the same thing in school. Everything is pretty simple except that I can't seem to figure out the last part (number 4).  And the end of number 3.
You might be interested in
A 30.0 kg box hangs from a rope. What is the tension (in N) in the rope if the box has an initial velocity of 2.0 m/s and is slo
hjlf

Answer:

360 N

Explanation:

m = 30kg    u = 2 m/s     a = -2m/s/s

Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s

the object will come to rest in 1 second but the force applied in that one second can be calculated by:

F = ma

F = 30 * -2

F = -60 N (the negative sign tells us that the force is acting downwards)

Now, calculating the force applied on the box due to gravity

letting g = -10m/s/s

F = ma

F = 30 * -10

F = -300 N (the negative sign tells us that the force is acting downwards)

Now, calculating the total downward force:

-300 + (-60) = -360 N

<em></em>

<em>Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction</em>

Therefore tension on the force = <u>360 N</u>

5 0
3 years ago
A truck with 28-in.-diameter wheels is traveling at 50 mi/h. Find the angular speed of the wheels in rad/min, *hint convert mile
solong [7]

Answer:

Angular speed ω=3771.4 rad/min

Revolution=5921 rpm

Explanation:

Given data

d=28in\\r=d/2=28/2=14in\\v=50mi/hr

To find

Angular speed ω

Revolution per minute N

Solution

First we need to convert the speed of truck to inches per mile

as

1 mile=63360 inches

1 hour=60 minutes

so

v=(50*\frac{63360}{60} )\\v=52800in/min

Now to solve for angular speed ω by substituting the speed v and radius r in below equation

w=\frac{v}{r}\\ w=\frac{52800in/min}{14in}\\ w=3771.4rad/min

To solve for N(revolutions per minute) by substituting the angular speed ω in the following equation

N=\frac{w}{2\pi }\\ N=\frac{3771.4rad/min}{2\pi }\\ N=5921RPM  

3 0
2 years ago
Which of the following is an example of acceleration? I. A car speeds up. II. A car slows down. III. A car travels in a straight
svetlana [45]
I., II., and IV. are examples of acceleration. III. isn't.
6 0
3 years ago
4.1 A steel spur pinion has a pitch of 5 teeth/in, 20 full-depth teeth, and a 20° pressure angle. The pinion runs at a speed of
Vesnalui [34]

Answer:

15.07 ksi

Explanation:

Given that:

Pitch (P) = 5 teeth/in

Pressure angle (\Phi) = 20°

Pinion speed (n_p ) = 2000 rev/min

Power (H) = 30 hp

Teeth on gear (N_G) = 50

Teeth on pinion (N_p) = 20

Face width (F) = 1 in

Let us first determine the diameter (d) of the pinion.

Diameter (d) = \frac{N}{P}

=\frac{20}{5}

= 4 in

From the values of Lewis Form Factor Y for (n_p ) = 20 ; at 20°

Y = 0.321

To find the velocity (V); we use the formula:

V = \frac{\pi d n_p}{12}

V = \frac{\pi *4*2000}{12}

V = 2094.40 ft/min

For cut or milled profile; the velocity factor (K_v) can be determined as follows:

K_v = \frac{2000+V}{2000}

K_v = \frac{2000+2094.40}{2000}

= 2.0472

However, there is need to get the value of the tangential load(W^t), in order to achieve that, we have the following expression

W^t=\frac{T}{\frac{d}{2} }

W^t = \frac{63025*H}{\frac{n_pd}{2}}

W^t = \frac{63025*30}{2000*\frac{4}{2}}

W^t = 472.69 lbf

Finally, the bending stress is calculated via the formula:

\sigma = \frac{K_vW^tp}{FY}

\sigma = \frac{2.0472*472.69*5}{1*0.321}

\sigma = 15073.07 psi

\sigma = 15.07 ksi

∴ The estimate of the bending stress = 15.07 ksi

4 0
3 years ago
Read 2 more answers
A 7.00-kg object undergoes an acceleration given by ax=3.00 and ay= 9.00 m/s2. Find (a) the components of the force acting on th
lord [1]

Answer:

66.4 N

Explanation:

From Newton's second law, <em>F </em>=<em> ma</em>

where <em>F</em> is the force, <em>m</em> is the mass and <em>a</em> is the acceleration.

Because the object has acceleration in two directions and the mass is constant, the force will be in two directions. The component of the forces are:

F_x = ma_x = (7.00\text{ kg})(3.00 \text{ m/s}^2) = 21.0\text{ N}

F_y = ma_y = (7.00\text{ kg})(9.00 \text{ m/s}^2) = 63.0\text{ N}

The magnitude of the resultant force is given by

F = \sqrt{F_x^2+F_y^2}

F = \sqrt{(21.0\text{ N})^2+(63.0\text{ N})^2} = \sqrt{(441.0\text{ N}^2)+(3969.0\text{ N}^2)} = \sqrt{(4410\text{ N}^2)} = 66.4 \text{ N}

7 0
3 years ago
Read 2 more answers
Other questions:
  • A cannonball is launched from the ground at an angle of 30 degrees above the horizontal and a speed of 30 m/s. Ideally (no air r
    12·1 answer
  • When the outermost energy level of an atom is full it tends to be?
    6·2 answers
  • A bird flies overhead from where you stand at an altitude of 270.0ĵ m and at a velocity horizontal to the ground of 14.0î m/is.
    9·1 answer
  • Coulomb measured the deflection of sphere A when spheres A and B had equal charges and were a distance d apart. He then made the
    8·1 answer
  • Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resi
    6·1 answer
  • A +0.2 µC charge is in an electric field. What happens if that charge is replaced by a +0.4 µC charge?
    8·1 answer
  • You want to raise the temperature of 22kg of water from 60°C to 95°C. If electricity costs $0.08/kWh, how much would it cost you
    8·1 answer
  • Match the following items.
    6·1 answer
  • What is transmitted by EM waves?
    11·1 answer
  • While rowing in a race, John does 132 J of work while pulling the oar 0.800 m.
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!