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3 years ago

Dos cargas puntuales q1 = −50μC y q2 = +30μC se encuentran

Physics

1 answer:

alina1380 [7]3 years ago

3 0

Answer:

Datos:

q1 = -50 μC = $50*10^{-6}$

q2 = +30 μC = $30*10^{-6}$

F = 10 N

a) x si la F = 10N

Aplicando la Ley de Coulomb:

x = $\sqrt\frac{k0 * q1 *q2}{F}$ = $\sqrt\frac{(9*10^{9} )*(50*10^{-6})*(30*10^{-6})}{10}$ = 1,162m

b) x si la F = 20 N

x= $\sqrt\frac{(9*10^{9} )*(50*10^{-6})*(30*10^{-6})}{20}$ = 0,822m

c)x si la F = 50 N

x = $\sqrt\frac{(9*10^{9} )*(50*10^{-6})*(30*10^{-6})}{50}$ = 0,520m

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Answer:

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Explanation:

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To convert 0.0000738 into scientific notation, follow these steps:

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Read 2 more answers

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Answer:

The speed of the sound wave is 350 m $s^{-1}$

Explanation:

Given

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Speed of sound wave = ?

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