Answer:
Number 6:
• From the formula of force:
• But we need to get the acceleration, from the first newtons equation of motion
• v is the final velocity, but v is zero because the bullet came to rest.
• u is the initial velocity, u = 350 m/s
• a is the acceleration that we need
• t is the time, t = 0.0018 seconds.
» let's now substitute:
[ negative shows retârdation or deceleration or decrease in speed ]
• Therefore, let's find the force:
mass = 6g = (6/1000) kg = 0.006 kg
Answer: 4
Explanation:
The dependent variable is the temperature of the water.
Answer:
the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.
Explanation:
This problem asks that we determine whether or not a critical flaw in a wide plate is subject to detection given the limit of the flaw detection apparatus (3.0 mm), the value of KIc (98.9 MPa m), the design stress (sy/2 in which s y = 860 MPa), and Y = 1.0.
Therefore, the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.
. For an elastic head-on (assumed) collision between equal masses, they simply swap velocities. The final velocities of objects 1 and 2 are 0 and v, respectively.
<span>2. mv = (2m)u </span>
<span>where u = final velocity. Then u = v1 = v2 = v/2 </span>
<span>3. Initially, p = (2m)v </span>
<span>final p = 2mv = 2mv1 + mv2 </span>
<span>But for an elastic head-on collision, we know that the </span>
<span>relative velocity of approach = relative velocity of separation, or </span>
<span>v = v2 - v1 </span>
<span>v2 = v + v1 </span>
<span>plug into final p: </span>
<span>2mv = 2mv1 + m(v + v1) = 2mv1 + mv + mv1 </span>
<span>mv = 3mv1 </span>
<span>v1 = v/3 </span>
<span>v2 = v + v/3 = 4v/3 </span>
<span>4. initial p = mv </span>
<span>final p = mv = (m + 3m)u = 4mu </span>
<span>u = v1 = v2 = v/4</span>
1.) false
2.) false
3.) true
4.) false
5.) false
6.) idk
7.) true
8.) true
9.) idk
10.) true
11.) true
12.) false
13.) false