Please Help!!!!!!!!!!!!!!!!!!!!!!!!!

7 I'LL GIVE BRAINLIST!!!

goldenfox [79]

Answer:

Below

Explanation:

1. Everest

2. Godwin Austen

3. Kangchenjunga

4. Lhotse

5. Makalu

6. Cho Oyu

7. Dhaulagiri

8. Manaslu

9. Nanga Parbat

10. Annapurna

Sorry I don't know anything about their types :(

I hope this helps you :)

4 0

3 years ago

Read 2 more answers

If you and your friend EACH apply 55N of force pushing against a wall for 10 minutes. How much work

alina1380 [7]

Answer: 0 J

Explanation: there’s no movement if it’s a wall

8 0

3 years ago

Suppose you walk 11 m in a direction exactly 24° south of west then you walk 21 m in a direction exactly 39° west of north. 1) H

DENIUS [597]

Answer:

(1) 42.94 m

(2) $16.02^\circ$

Explanation:

Let us first draw a figure, for the given question as below:

In the figure, we assume that the person starts walking from point A to travel 11 m exactly $24^\circ$ south of west to point B and from there, it walks 21 m exactly $39^\circ$ west of north to reach point C.

Let us first write the two displacements in the vector form:

$\vec{AB} = (-11\cos 24^\circ\ \hat{i}-11\sin 24^\circ\ \hat{j})\ m =(-10.05\ \hat{i}-4.47\ \hat{j})\ m\\\vec{BC} = (-21\sin 39^\circ\ \hat{i}+21\cos 39^\circ\ \hat{j})\ m =(-31.22\ \hat{i}+16.32\ \hat{j})\ m$

Now, the vector sum of both these vectors will give us displacement vector from point A to point C.

$\vec{AC}=\vec{AB}+\vec{BC}\\\Rightarrow \vec{AC}=(-10.05\ \hat{i}-4.47\ \hat{j})\ m+(-31.22\ \hat{i}+16.32\ \hat{j})\ m\\\Rightarrow \vec{AC}=(-41.25\ \hat{i}+11.85\ \hat{j})\ m$

Part (1):

the magnitude of the shortest displacement from the starting point A to point the final position C is given by:

$AC=\sqrt{(-41.25)^2+(11.85)^2}\ m= 42.94\ m$

Part (2):

As the vector AC is coordinates lie in the third quadrant of the cartesian vector plane whose angle with the west will be positive in the north direction.

The angle of the shortest line connecting the starting point and the final position measured north of west is given by:

$\theta = \tan^{-1}(\dfrac{11.85}{41.27})\\\Rightarrow \theta = 16.02^\circ$

4 0

3 years ago

In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, where the radius of the orbit is

Alchen [17]

Answer:

(a) Electric force will be $77.285\times 10^{-9}N$

(B) Velocity $v=2.1522\times 10^6m/sec$

Explanation:

We have given that radius of the circular orbit $r=0.546\times 10^{-10}m$

Charge on electron $e=1.6\times 10^{-19}C$

(A) According to coulomb's law electric force between two charges is given by

$F=\frac{kq}{r^2}$

So electric force $F=\frac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.546\times 10^{-10})^2}=77.285\times 10^{-9}N$

We know that centripetal force is given by $F=\frac{mv^2}{r}$

So $\frac{9.11\times 10^{-31}\times v^2}{0.546\times 10^{-10}}=77.285\times 10^{-9}$

$v=2.1522\times 10^6m/sec$

8 0

3 years ago

a man weighs 600 n while on the surface of earth. if he is transported to the planet mythos which has the same mass as earth but

faltersainse [42]

Answer:

24N

Explanation:

Calculation for what his weight would be

Let his WEIGHT on the surface of earth be 600 and Let the RADIUS be 25 which is (5^²) because we were told that the radius is FIVE TIMES larger than earths

Now let calculate his weight using this formula

Weight=Weight on Earth/Radius

Let plug in the formula

Weight=600N/5^²

Weight=600N/25

Weight=24N

Therefore his weight would be 24N

3 0

3 years ago