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Inga [223]
3 years ago
12

Subtract the equations. 7x+2y=17 - (3x+2y=3)

Mathematics
2 answers:
Aneli [31]3 years ago
5 0

= 7x+2y=17

- (3x+2y=3)


= 7x+2y=17

 -3x-2y=-3


= 7x+2y=17

 -3x-2y=-3

= 4x = 14


= x = 14/4

MaRussiya [10]3 years ago
4 0

Answer: x=\dfrac{7}{2}

Step-by-step explanation:

The given equations are:

7x+2y=17
............................................(1)\\\\\text{ and }3x+2y=32..............................(2)/tex]When we subtract equation (2) from equation (1) , we subtract the right hand side of equation (1) from the right hand side of equation (2) and similarly for left side equation, we get[tex]7x-3x+2y-2y=17-3\\\\\Rightarrow\(7-3)x+(2-2)y=17-3 \\\\\Rightarrow\ 4x+0=14\\\\\Rightrrow\ x=\dfrac{14}{4}=\dfrac{7}{2}

Thus when we subtract the given equations, we get x=\dfrac{7}{2}

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