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Dmitry_Shevchenko [17]
3 years ago
5

A tissue cross-section viewed on a microscope slide shows a cell of almost rectangular shape with dimensions 6.9 × 10-4 cm by 1.

1 × 10-3 cm. Calculate the cross-sectional area of the cell. Express the area in powers of ten notation and use the appropriate number of significant digits for the number multiplying the power of 10.
Physics
1 answer:
zimovet [89]3 years ago
4 0

Answer:

The  cross-sectional  area is A = 7.59 *10^{-11} \  m^2

Explanation:

From the question we are told that

   The dimension of the cell is    6.9 × 10-4 cm by 1.1 × 10-3 cm = 6.9*10^{-6} \ m \ by\  1.1*10^{-5} \  m

   Generally the cross-sectional area is mathematically represented  as

    A  =  6.9*10^{-6}   *  1.1*10^{-5}

=>   A = 7.59 *10^{-11} \  m^2

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3 years ago
what are the speeds of (a) a proton that is accelerated from rest through a potential difference of −1000 v−1000 v and (b) an el
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1 year ago
How do I solve this step by step? I’m really confused
LekaFEV [45]

Step-#1:

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Step #2:

Now, ignore the wire on the left.

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Step #3:

Take the two sets of magnitude and direction that you wrote down

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3 years ago
A rope of negligible mass is wrapped around a 225-kg solid cylinder of radius 0.400 m. The cylinder is suspended several meters
vodomira [7]

Answer:

a)6.67 m/s2

b)16.7 rad/s2

c)increasing angular acceleration

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a) It's because the system is not just mass of the man, it consists of the man holding a rope wrapped around a cylinder, not just a man free falling. So you would have to consider the rotating cylinder under the torque created by the man gravity force.

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4 years ago
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