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aleksandrvk [35]
3 years ago
5

A straightforward method of finding the density of an object is to measure its mass and then measure its volume by submerging it

in a graduated cylinder. What is the density (in g/cm3) of a 220g rock that displaces 75.0 cm3 of water
Physics
1 answer:
Verizon [17]3 years ago
5 0

Answer: 2.9 g/cm^{3}

Explanation:

from the question we are given the following:

mass of rock = 220 g

volume of displaced water = 75 cm^{3}

the density of an object is gotten from the formula density = \frac{mass}{volume}

From the question, we were given the mass of a rock and volume of water the rock displaces.

When water is placed in a graduated cylinder and a rock is placed in the water, the volume of water the rock displaces is the increase in the reading of water after the rock has been put in it. The amount of water displaced is known as the volume of the rock.

therefore volume of the rock = volume of water displaced

density = \frac{220}{75} = 2.9 g/cm^{3}

You might be interested in
A storm 10.0 km in diameter has wind speeds of 10.0 m/s. What is its angular velocity in radians per second
Aloiza [94]

Answer:

The value is w= 2*10^{-3} \  rad/s

Explanation:

From the question we are told that

  The diameter of the storm is  d =  10.0 \  km  =  10 000 \  m

   The wind speed is  v  =  10.0 \  m/s

   

Generally the radius is mathematically represented as

       r =  \frac{d}{2}

=>  r =  \frac{10000}{2}

=>    r =  5000 \ m

Generally the angular velocity is mathematically represented as  

        w= \frac{v}{r}

=>     w= \frac{10}{5000}

=>     w= 2*10^{-3} \  rad/s

3 0
3 years ago
Alondra applies 24 N of force to the end of a stick (a type of lever) to open a can of paint.
Assoli18 [71]

Answer:

1/4

Explanation:

Mechanical Advantage = Load/Effort

Given

Effort applied = 24N

Load = 6N

Substitute

MA = 6/24

MA = 1/4

Hence the mechanical advantage is 1/4

8 0
2 years ago
Read 2 more answers
Air at 27oC and 1 atm flows over a flat plate 40 cm in length and 1 cm in width at a speed of 2 m/s. The plate is heated over it
irga5000 [103]

Answer:

Heat transferred = 22.9 watt

Explanation:

Given that:

T_1 = 27°C = (273 + 27) K = 300 K

T_2= 600°C = (600 +273) K = 873 K

speed v = 2 m/s

length x = 40 cm = 0.4 cm

width = 1 cm = 0.001 m

The heat transferred from the plate can be calculate by using the formula:

Heat transferred = h×A ×ΔT

From the tables of properties of air, the following values where obtained.

k = 0.02476 \ W/m.k  \\ \\  \rho = 1.225 \ kg/m^3 \\ \\ \mu = 18.6 \times 10^{-6} \ Pa.s \\ \\ c_p = 1.005 \ kJ/kg

To start with the reynolds number; the formula for calculating the reynolds number can be expressed as:

reynolds number = \dfrac{\rho \times v \times x }{\mu}

reynolds number = \dfrac{1.225 \times 2 \times 0.4}{18.6 \times 10^{-6}}

reynolds number = \dfrac{0.98}{18.6 \times 10^{-6}}

reynolds number = 52688.11204

Prandtl number = \dfrac{c_p \mu}{k}

Prandtl number = \dfrac{1.005 \times 18.6 \times 10^{-6} \times 10^3}{0.02476}

Prandtl number = \dfrac{0.018693}{0.02476}

Prandtl number = 0.754963

The nusselt number for this turbulent flow over the flat plate  can be computed as follows:

Nusselt no = \dfrac{hx}{k} = 0.0296 (Re) ^{0.8} \times (Pr)^{1/3}

\dfrac{h \times 0.4}{0.02476} = 0.0296 (52688.11204) ^{0.8} \times (0.754968)^{1/3}

\dfrac{h \times 0.4}{0.02476} =161.4252008}

h  =\dfrac{161.4252008 \times 0.02476}{ 0.4}

h = 9.992 W/m.k

Recall that:

The heat transferred from the plate can be calculate by using the formula:

Heat transferred = h×A ×ΔT

Heat transferred = h\times A \times (T_2-T_1)

Heat transferred = 9.992 × (0.4 × 0.01) ×(873-300)

Heat transferred = 22.9 watt

6 0
3 years ago
Temperature is generally proportional to a substance's _______.
daser333 [38]

rotational kinetic energy of it's particles

6 0
3 years ago
A 20kg mass approaches a spring at a speed of 30 m/s. The mass compresses the spring 12cm before coming to a stop. Calculate the
Oksana_A [137]

Answer:

625000 N/ m

Explanation:

m= 20 kg

v= 30 m/s

x= 12 cm

k = ?

Here when the mass when hits at spring its speed is

Vi= 30 m/s

Finally it comes to rest after compressing for 12 cm

i-e Vf = 0 m/s

Distance= S= 12 cm = 0.12 m

using

2aS= Vf2 - Vi2

==> 2a ×0.12 = o- 30 × 30

==> a = 900 ÷ 0.24 = 3750 m/sec2

Now we know;

F = ma

F= -Kx

==> ma= -kx

==> 20 × 3750 = -K × 0.12

==> k = 625000 N/ m

5 0
2 years ago
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