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aleksandrvk [35]
3 years ago
5

A straightforward method of finding the density of an object is to measure its mass and then measure its volume by submerging it

in a graduated cylinder. What is the density (in g/cm3) of a 220g rock that displaces 75.0 cm3 of water
Physics
1 answer:
Verizon [17]3 years ago
5 0

Answer: 2.9 g/cm^{3}

Explanation:

from the question we are given the following:

mass of rock = 220 g

volume of displaced water = 75 cm^{3}

the density of an object is gotten from the formula density = \frac{mass}{volume}

From the question, we were given the mass of a rock and volume of water the rock displaces.

When water is placed in a graduated cylinder and a rock is placed in the water, the volume of water the rock displaces is the increase in the reading of water after the rock has been put in it. The amount of water displaced is known as the volume of the rock.

therefore volume of the rock = volume of water displaced

density = \frac{220}{75} = 2.9 g/cm^{3}

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A climber pulls herself 8 meters upwards with a force of 150 Newtons. If it takes her 16 seconds to cover the 8 meters, how much
mr Goodwill [35]

Answer:

 P = 75 W

Explanation:

given,

Distance, L = 8 m

Force,F = 150 N

Time, t = 16 s

Work by the climber

Work done = Force x displacement

W = F. L

W = 150 x 8

W = 1200 J

We know,

Power =\dfrac{Work\ done}{time}

P =\dfrac{1200}{16}

 P = 75 W

Hence, Power climber is using to climb is equal to 75 W.

3 0
3 years ago
Find the moments of inertia Ix, Iy, I0 for a lamina that occupies the part of the disk x2 y2 ≤ 36 in the first quadrant if the d
Tasya [4]

Answer:

I(x)  = 1444×k ×{\pi}

I(y)  = 1444×k ×{\pi}

I(o) = 3888×k ×{\pi}  

Explanation:

Given data

function =  x^2 + y^2 ≤ 36

function =  x^2 + y^2 ≤ 6^2

to find out

the moments of inertia Ix, Iy, Io

solution

first we consider the polar coordinate (a,θ)

and polar is directly proportional to a²

so p = k × a²

so that

x = a cosθ

y = a sinθ

dA = adθda

so

I(x) = ∫y²pdA

take limit 0 to 6 for a and o to \pi /2 for θ

I(x) = \int_{0}^{6}\int_{0}^{\pi/2} y²p dA

I(x) = \int_{0}^{6}\int_{0}^{\pi/2} (a sinθ)²(k × a²) adθda

I(x) = k  \int_{0}^{6}a^(5)  da ×  \int_{0}^{\pi/2}  (sin²θ)dθ

I(x) = k  \int_{0}^{6}a^(5)  da ×  \int_{0}^{\pi/2}  (1-cos2θ)/2 dθ

I(x)  = k ({r}^{6}/6)^(5)_0 ×  {θ/2 - sin2θ/4}^{\pi /2}_0

I(x)  = k × ({6}^{6}/6) × (  {\pi /4} - sin\pi /4)

I(x)  = k ×  ({6}^{5}) ×   {\pi /4}

I(x)  = 1444×k ×{\pi}    .....................1

and we can say I(x) = I(y)   by the symmetry rule

and here I(o) will be  I(x) + I(y) i.e

I(o) = 2 × 1444×k ×{\pi}

I(o) = 3888×k ×{\pi}   ......................2

3 0
3 years ago
I don’t understand ???? I can use any help you can give?
evablogger [386]
Crust and atmosphere earth outer crust and the mantel is the most important thing about the mantle are is what it is made up if and last is the core
3 0
3 years ago
If the mass of a material is 50 grams and the volume of the material is 12 cm^3, what would the density of the material be?
AlekseyPX
The density of the material would be 
25/6 grams per cm^3.
to obtain the result above this is what we do:
density is calculated as: (the mass of the given material or object) / volume of the material 
which leads us to 50grams /12cm^3
 
4 0
3 years ago
A set of charged plates 0.00262 m apart has an electric field of 155 N/C between them. What is the potential difference between
mylen [45]

Answer: The potential difference between the plates = 0.4061V

Explanation:

Given that the

Electric field strength E = 155 N/C

Distance d = 0.00262 m

From the definition of electric field strength, is the ratio of potential difference V to the distance between the plates. That is

E = V/d

Substitute E and d into the above formula

155 = V/0.00262

Cross multiply

V = 155 × 0.00262

V = 0.4061 V

The potential difference between the plates is 0.4061 V

5 0
2 years ago
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