Answer:
14 L
Explanation:
The ice water will have to be warmed up to 37 oC
Quantity of heat gain the ice water = mcΔT
where m is the mass of water, c is the specific heat capacity of water
heat gain = heat loss
heat expected the body to lose = 520kcal = 520 × 4184 J ( 1 kcal is 4184 J)
520 × 4184 = 4200 × m × 37
m = (520 × 4184) / ( 4200 × 37) where specific heat capacity of water is 4200J/KG.K
but density = m/V where V is volume in m³
m = ρ×V
replace m with the above formula
ρV = (520 × 4184) / ( 4200 × 37) and density of water is 1000kg/m³
V = (520 × 4184) / (4200 × 37 × 1000) = 0.014 m³ = 0.014 × 1000 ( 1m³ = 1000L) = 14 L
exercise will be better as it is not quite possible to drink this (14 L) volume of ice cold water.
Using SUVAT
U = 0 m/s
V = 30 m/s
A = ?
S = 45 m
Its “A“ primary waves!!!!!!
I think its supposed to be something like this
Use the terminal velocity formula, v = the square root of ((2*m*g)/(ρ*A*C)).<span>m = mass of the falling object.
</span><span>g = the acceleration due to gravity.
</span><span>p = the density of the fluid the object is falling through.
</span><span>a = the projected area of the object.
</span><span><span>c = the drag coefficient.</span></span>
My grandfather is a whiz at math so helped me figure it out