Answer:
(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.
Explanation:
According to the Kelvin–Planck statement of the second law of thermodynamics ,it is not possible to construct a device which operates in cycle and does not produce effect on the environment than the production of work.
We know that
Coefficient of performance is the ratio of desired effect to the work input in a cycle.
Given all option is correct but most appropriate option is a.
So the option a is correct
(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.
Answer:
a. There are only 5 electrons in 2p. 2p should be filled with 6 electrons prior to 3s and 3p
b. There are 8 electrons in 2p. 2p should be filled only with 6 electrons (not 8)
Explanation:
The typical electron configuration: 1s2 2s2 2p6 3s2 3p6
a. There are only 5 electrons in 2p
=> should be 1s2 2s2 2p6 3s2 3p2
b. There are 8 electrons in 2p
=> should be 1s2 2s2 2p6 3s2 3p1
Answer:
Explanation:
For this we're going to take the help of a concept called Graham's law which says
The rate of diffusion of a gas is inversely proportional to the square root of its molar mass
So
Molecular masses of
N2 : 28 g/mole
He: 4 g/mole
O2: 32 g/mole
Co 2 : 44 g/mole
Therefore the order
He>N2>O2>Co2
Answer:
False. The balance equation for the redox reaction is:
2Fe + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃
Explanation:
Let's think the half reactions:
Fe → Fe³⁺ + 3e⁻
The Fe increase the oxidation state. This is the oxidation, where Fe changes from 0 to +3
Cu²⁺ + 2e⁻ → Cu
This is the reduction. Cu changes from 2+ to 0
We multiply the half reaction x2 and x3 to balance the electrons
2Fe → 2Fe³⁺ + 6e⁻
3Cu²⁺ + 3e⁻ → 3Cu
And we sum both
2Fe + 3Cu²⁺ + 6e⁻ → 3Cu + 2Fe³⁺ + 6e⁻
The electrons are cancelled, so the balance reaction is:
2Fe + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃