All categories

3 years ago

An object with a mass of 4.0 kg has a force of 12.0 newtons applied to it. What is the resultant acceleration of the object?

Chemistry

1 answer:

Zigmanuir [339]3 years ago

3 0

Answer:

3m/s²

Explanation:

Force applied to an object can be calculated thus;

F = ma

Where;

F = force applied (Newtons)

m = mass of substance (kg)

a = acceleration (m/s²)

According to the information provided in this question, F = 12.0 newtons, m = 4.0 kg, a = ?

Derived from F = m.a

We have; a = F/m

a = 12/4

a = 3

The resultant acceleration of the object is 3m/s².

You might be interested in

When backpacking in the wilderness, hikers often boil water to sterilize it for drinking. Suppose that you are planning a backpa

Pavlova-9 [17]

Answer:

2.104 L fuel

Explanation:

Given that:

Volume of water = 35 L = 35 × 10³ mL

initial temperature of water = 25.0 ° C

The amount of heat needed to boil water at this temperature can be calculated by using the formula:

$q_{boiling} = mc \Delta T$

where

specific heat of water c= 4.18 J/g° C

$q_{boiling} = 35 \times 10^{3} \times \dfrac{1.00 \ g}{1 \ mL} \times 4.18 \ J/g^0 C \times (100 - 25)^0 C$

$q_{boiling} = 10.9725 \times 10^6 \ J$

Also; Assume that the fuel has an average formula of C7 H16 and 15% of the heat generated from combustion goes to heat the water;

thus the heat of combustion can be determined via the expression

$q_{combustion} =- \dfrac{q_{boiling}}{0.15}$

$q_{combustion} =- \dfrac{10.9725 \times 10^6 J}{0.15}$

$q_{combustion} = -7.315 \times 10^{7} \ J$

$q_{combustion} = -7.315 \times 10^{4} \ kJ$

For heptane; the equation for its combustion reaction can be written as:

$C_7H_{16} + 11O_{2(g)} -----> 7CO_{2(g)}+ 8H_2O_{(g)}$

The standard enthalpies of the products and the reactants are:

$\Delta H _f \ CO_{2(g)} = -393.5 kJ/mol$

$\Delta H _f \ H_2O_{(g)} = -242 kJ/mol$

$\Delta H _f \ C_7H_{16 }_{(g)} = -224.4 kJ/mol$

$\Delta H _f \ O_{2{(g)}} = 0 kJ/mol$

Therefore; the standard enthalpy for this combustion reaction is:

$\Delta H ^0= \sum n_p\Delta H^0_{f(products)}- \sum n_r\Delta H^0_{f(reactants)}$

$\Delta H^0 =( 7 \ mol ( -393.5 \ kJ/mol) + 8 \ mol (-242 \ kJ/mol) -1 \ mol( -224.4 \ kJ/mol) - 11 \ mol (0 \ kJ/mol))$

$\Delta H^0 = (-2754.5 \ \ kJ - 1936 \ \ kJ+224.4 \ \ kJ+0 \ \ kJ)$

$\Delta H^0 = -4466.1 \ kJ$

This simply implies that the amount of heat released from 1 mol of C7H16 = 4466.1 kJ

However the number of moles of fuel required to burn $7.315 \times 10^{4} \ kJ$ heat released is:

$n_{fuel} = \dfrac{q}{\Delta \ H^0}$

$n_{fuel} = \dfrac{-7.315 \times 10^{4} \ kJ}{-4466.1 \ kJ}$

$n_{fuel} = 16.38 \ mol \ of \ C_7 H_{16$

Since number of moles = mass/molar mass

The mass of the fuel is:

$m_{fuel } = 16.38 mol \times 100.198 \ g/mol}$

$m_{fuel } = 1.641 \times 10^{3} \ g$

Given that the density of the fuel is = 0.78 g/mL

and we know that :

density = mass/volume

therefore making volume the subject of the formula in order to determine the volume of the fuel ; we have

volume of the fuel = mass of the fuel / density of the fuel

volume of the fuel = $\dfrac{1.641 \times 10^3 \ g }{0.78 g/mL} \times \dfrac{L}{10^3 \ mL}$

volume of the fuel = 2.104 L fuel

3 0

4 years ago

________________________________________ is a reaction in which the conversion of reactants into products and the conversion of

vivado [14]

Answer is: reversible reaction.
The concentrations of reactants and products in an equilibrium mixture are determined by the equilibrium constant K.
When writing chemical equations for reversible reactions, two arrows are used, for example: NH₄Cl(s) ⇆ NH₃(g) + HCl(g) or
CuSO₄(s) + 5H₂O(l) ⇆ CuSO₄·5H₂O(s).

6 0

4 years ago

Balance this equation. If a coefficient of "1" is required, choose "blank" for that box.

Kitty [74]

Answer: 2 C2H4 + 6 O2 => 4 CO2 + 4 H2O

Explanation:The coefficient are as follows: 2: 6: 4: 4

Each atom on the reactant and product side are equal.

Reactant Product

C 2x2 = 4 4x1 = 4

H 2x4 = 8 4x2 = 8

O 6x2 = 12 (4x2) + 4 = 12

7 0

3 years ago

Why does a higher concentrations make a reaction go faster?

antoniya [11.8K]

Its much stronger than if something was not strong.

8 0

3 years ago

If you keep buying despite a price increase, your demand is what?

prisoha [69]

The best answer is C! Hope I helped :D

3 0

3 years ago

Read 2 more answers