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Scilla [17]
3 years ago
6

A sample gaseous CO exerts a pressure of 45.6mm Hg in a 56.0L flask at 22 C. If the gas is released into a 2.70 x 10^4 liter roo

m, what is the partial pressure of the CO in the room at 22 C ?
Chemistry
1 answer:
SSSSS [86.1K]3 years ago
3 0
P1 = 45.6, V1 = 56.0L, V2 = 2.70 x 10^4, P2 = ??
Use P1V1 = P2V2 --> P2 = P1V1/V2
P2 = (45.6)(56)/(27000)
P2 = 2554/27000 = 0.095 mmHg in the room
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Identify the correct descriptions of beta particles.
FrozenT [24]

Answer:

a. A beta particle has a negative charge. d. A beta particle is a high-energy electron.

Explanation:

Identify the correct descriptions of beta particles.

a. A beta particle has a negative charge. YES. A beta particle is originated in the following nuclear reaction: ¹₀n ⇒ ¹₁H + ⁰₋₁e (beta particle.)

b. A beta particle contains neutrons. NO. It is a electron originated in the nucleus.

c. A beta particle is less massive than a gamma ray. NO. Gamma rays don't have mass while a beta particle has a mass which is half of one thousandth of the mass of a proton.

d. A beta particle is a high-energy electron. YES. Beta particles are nuclear originated hig-energy electrons.

6 0
3 years ago
Density of distilled water?? What is the density of distilled water???
MAXImum [283]
The density is one gram per mL, so 1.
3 0
3 years ago
For a colligative property such as freezing point depression, :________
neonofarm [45]
A possible answer is b
5 0
2 years ago
A pure white crystalline compound was found to melt at 112.5-113.0oC when taken on a melting point apparatus, and on further hea
Sergeeva-Olga [200]

According to the question, the determined melting point of the compound is 112.5-113.0oC. When the solidified compound was retried, the melting point was found to be 133.6-154.5oC. This greater range higher than  112°C is caused by reusing samples leads to errors.

A pure sample is known by its sharp melting point. A pure sample does not melt over a large range. We can see this in the predetermined melting points of the pure sample(112.5-113.0oC).

However, reusing a sample introduces errors because the pure sample may become contaminated leading to a larger and higher range of melting point (133.6-154.5oC) which is far above  112°C.

Learn more: brainly.com/question/5325004

8 0
2 years ago
An aqueous solution of glucose has molality of 6.81 and a density of 1.2 g/ml what is the molarity of glucose in the solution
andriy [413]

Answer:

the molarity is 3.68 moles/L

Explanation:

the molality of the solution of sucrose is

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from the density

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therefore there is 1000 gr of water in 1855.71 ml

then the molarity M is

M= moles of glucose / L of solution = (moles of glucose /  Kg of solvent) *  (Kg of solvent/L of solution) = 6.81 moles/Kg * 1Kg/1.85 L = 3.68 moles/L

M= 3.68 moles/L

Note:

- Would be wrong in this case to assume density of water = 1 Kg/L since the solution is heavily concentrated in glucose and therefore the density of water deviates from its pure value.

3 0
3 years ago
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