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EleoNora [17]
3 years ago
6

Which of the following methods estimates geologic events by comparing the objects to the layer of Earth they were discovered in?

Fossil dating Geologic dating Radioactive dating Relative dating
Chemistry
2 answers:
sveta [45]3 years ago
6 0

The answer is; Relative dating

This type of dating is not concerned with determining the absolute age of rock. It compares between rock layer and determines which is younger or older in comparison. Therefore relative dating is significant in arranging geologic events based on the stratigraphy of rock layers.  


NNADVOKAT [17]3 years ago
6 0

Answer: Relative dating

Explanation:

Relative dating is a technique of identifying the age of the material whether fossil or rocks by comparing them with the surrounding materials. This method takes into consideration the order of the geological events took place on earth. This can be done by stratigraphy. In stratigraphy the layers of the rocks and sediments are compared to determine the age of the object (fossil, rock). This method does not help in determining the exact or absolute age of the object.

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A sample of table sugar (sucrose c12h22o11) has a mass of 3.115 g
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Which of the following radioactive emissions is the least penetrating?
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2 years ago
Water (with density of 1000 kg/m3) with the mass flowrate of 10 kg/sec is flowing into an empty tank. The outlet volumetric flow
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   Rate of accumulation of water within the tank = rate of mass of water entering the tank - rate of mass of water releasing from the tank

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      \rho A_{c} \frac{dh}{dt} = 10 - (0.01) \rho h

   \frac{dh}{dt} + \frac{0.01 \rho h}{\rho A_{c}} = \frac{10}{\rho A_{c}}

          [/tex]\frac{dh}{dt} + \frac{0.01}{0.01}h[/tex] = \frac{10}{\rho A_{c}}

                       A_{c} = 0.01 m^{2}

              \frac{dh}{dt} + h = 1

                  \frac{dh}{dt} = 1 - h

               \frac{dh}{1 - h} = dt  

                \frac{ln(1 - h)}{-1} = t + C      

Given at t = 0 and V = 0  

                         A \times h = 0  

 or,                     h = 0

                 -ln(1 - h) = t + C

Initial condition is -ln(1) = 0 + C

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                So,   -ln(1 - h) = t

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(a)    Using equation (1) calculate time to fill the tank up to 0.6 meter from the bottom as follows.

                    t = ln (\frac{1}{1 - h})  

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(b)   As maximum height of water level in the tank is achieved at steady state that is, t = \infty.  

                    1 - h = exp (-t)

                    1 - h = 0  

                         h = 1

Hence, we can conclude that the tank cannot be filled up to 2 meters as maximum height achieved is 1 meter.

                 

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