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Tcecarenko [31]
3 years ago
12

A sample of hydrogen gas at a pressure of 0.926 atm and a temperature of 29.5 C, occupies a volume of 457 mL. If the gas is allo

wed to expand at constant temperature until its pressure is 0.447 atm, the volume of the gas sample will be ___ mL.
Chemistry
1 answer:
klio [65]3 years ago
4 0

Answer:

V₂ = 946.72 mL

Explanation:

Given data;

Initial pressure = 0.926 atm

Initial volume = 457 mL

Temperature = constant = 29.5°C

Final pressure = 0.447 atm

Final volume = ?

Solution:

The given problem will be solved through the Boyle's law,

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

by putting values,

P₁V₁ = P₂V₂

0.926 atm × 457 mL = 0.447 atm × V₂

V₂ = 423.18 atm. mL/ 0.447 atm

V₂ = 946.72 mL

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Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

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2\times 96500=193000C is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

14\times 1000g=14000g of copper is deposited by =\frac{193000}{63.5}\times 14000=42551181 C

To calculate the time required, we use the equation:

I=\frac{q}{t}

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

40.0=\frac{42551181 C}{t}\\\\t=1063779sec

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, 1063779s\times \frac{1hr}{3600s}=295hr

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0
3 years ago
Select the correct Answers.
Mandarinka [93]

Answer:

3. The temperatures of the two substances equalize.

Explanation:

  • As two objects at different temperatures are placed in contact, heat is transferred from the warmer to the cooler object until the temperature of the two objects be the same.
  • The amount of heat that is transferred from the warmer object is equal to the amount of heat that is transferred into the cooler object.
  • This is in agreement with the law of conservation of energy.
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8 0
4 years ago
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Answer:

D.

Explanation:

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4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)
Crazy boy [7]

1. The volume of ammonia consumed in the reaction is 23.2 L

2. The volume of oxygen consumed in the reaction is 29 L

<h3>Balanced equation</h3>

4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(g)

From the balanced equation above,

6 L of H₂O were produced from 4 L of NH₃ and 5 L of O₂

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From the balanced equation above,

6 L of H₂O were produced from 4 L of NH₃

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Answer with Explanation:

Different versions of a gene are called alleles. Alleles are described as either dominant or recessive depending on their associated traits. Since human cells carry two copies of each chromosome they have two versions of each gene.

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