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3 years ago

What is the electron configuration of the calcium ion?

Chemistry

2 answers:

Elanso [62]3 years ago

4 0

[Ar] 4s²
Let me know if you want a step by step!
Hope that helps

likoan [24]3 years ago

3 0

Answer: Calcium ion Ca² : 1 s² 2s² 2p ^6 (sorry I don't get 6 similar way as 2) 3s² 3p^6

Also 18 electrons, because Calcium donates two 4s electrons

Explanation:

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Draw the curved arrow mechanism for the reaction between (2S,3S)-3,5-dimethylhexan-2-ol and PCl3. Note the specific instructions

Vikki [24]

Answer:

(2R,3S)-2-chloro-3,5-dimethylhexane

Explanation:

As first step we have the attack of the OH group to the P atom in the PCl3 and one of the Cl atoms would leave. Then we will have a rearrangement to produce a double bond with the oyxgen on the OH. Finally the Cl produced will attack the carbon in a Sn2 substitution reaction to produce the halide with an opposite configuration.

4 0

3 years ago

The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:

aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium: 0.50M - x x x

The equilibrium constant (Ka₁) is:

$K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}$

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

$[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M$

Similarly, from the second dissociation of sulfurous acid we have:

HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium: 7.94x10⁻²M - x x x

The equilibrium constant (Ka₂) is:

$K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}$

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

$[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M$

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0

3 years ago

What aspect of metallic bonding is responsible for malleability ductility and conductivity of metals?

ANTONII [103]

Bonds are forces of attractions between atoms formed by the transfer of electrons or sharing of electrons. Metallic bond is a type bond that exist in metallic structures where the atoms of the metals attracts the sea of electrons in the structure.It is these metallic bonds that results to the malleability , ductility and conductivity of metals because in that the sea of electrons makes them conduct electricity. In addition the atoms of metals in the structure are ions which can slide past each other in the sea of electrons.

4 0

2 years ago

If kerosene has a specific gravity of 0.820, what force will be exerted on the circular bottom of a cylindrical kerosene tank th

Svet_ta [14]

Answer:

$F = 774146.534\,N$