Answer:
NH3 ------dipole - dipole forces
CH3OH ------ dipole - dipole forces
AlBr3 ------- ion - dipole forces
AlCl3 ------- ion - dipole forces
Explanation:
Let us recall that water is a polar molecule. This means that water has a positive as well as a negative end. NH3 also has a dipole. The interaction between solute and solvent dipoles leads to the dissolution of NH3 in water. Hence the strongest intermolecular force here is dipole - dipole forces.
Similarly, CH3OH possesses a polar -O-H group which can interact with water via dipole - dipole interaction as its strongest intermolecular force.
As for AlBr3 and AlCl3, the two substances dissociate into ions in solution and these ions interact with the dipole in water via ion - dipole interaction as its strongest intermolecular interaction.
Answer:
V₂ = 37.71 mL
Explanation:
Given data:
Initial volume = 85.0 mL
Initial pressure = 1 atm
Initial temperature = 20°C (20 +273 = 293 K)
Final temperature = 91°C (91+273 = 364 K)
Final volume = ?
Final pressure = 2.8 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm× 85.0 mL × 364 K / 293 K × 2.8 atm
V₂ = 30940 atm.mL.K / 820.4 K.atm
V₂ = 37.71 mL
The given data is as follows:
Element 1st IE
1 1310 kJ/mol
2 1011 kJ/mol
3 418 kJ/mol
4 2080 kJ/mol
5 947 kJ/mol
Ionization energy is the amount of energy required to remove an electron from an atom. It reflects the tendency of an atom to give away electrons readily. Lower the IE, more easily will the electron be lost. Low values of IE are characteristic of metals whereas, non-metals have higher IE values.
Based on the given data:
Element 4 is likely to be a non-metal
Element 3 is likely to be a metal