Answer:
9.24% the percent of Mg in the mixture.
Explanation:
Mass of silver bromide = 1.1739 g
Moles of silver bromide = 
1 mole of AgBr has 1 mole of bromine atom.Then 0.006244 moles AgBr has 0.006244 mole bromine atom.
Moles of bromine atoms = 0.006244 moles
Magnesium bromide has 2 moles of bromine atom.Then 0.006244 moles of bromine atoms will be in :
Magnesium bromide has 1 mole magnesium atom, then 0.003122 moles of magnesium bromide will have :
magnesium atom
Mass of 0.003122 moles of magnesium :
0.003122 mol × 24 g/mol = 0.07493 g
Mass of the sample = 0.8107 g
Percentage of magnesium in the sample ;
9.24% the percent of Mg in the mixture.
Answer:
The shape of the BF3 molecule is best described as trigonal planar.
Explanation:
The Lewis Structure for BF3 is like this:
_ _
| F | | F |
\ /
B
|
| F |
---
It forms three angles of 120° each. The bonds are in the same planar that's why it is trigonal planar and they are exactly the same.
Boron and Fluorine have 3 covalent bonds, produced by electronic promotion that enables the 2py and 2pz orbitals, leaving an electron to pair in the 2px. So boron will have 3 possible electrons to pair in 2s1, 2px and 2py, remember that electronic configuration for B is 1s2, 2s2, 2p1
By hybridization between the orbitals 2s2 and 2p1, the electrons of F, can joined to make the covalent bond. The new B configuration is 1s2, 2s1, 2px1, 2py1 (these last three, hybrid orbitals)
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