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Mama L [17]
2 years ago
5

What type of bonding occurs in a sample of pure chromium, cr? in other words, how is one chromium atom held to another chromium

atom?
Chemistry
1 answer:
spayn [35]2 years ago
4 0

Chromium is a metal in nature. So when one chromium is bonded to another chromium, there is a weak intermolecular forces which helds them together which we call as “metallic bonding”.

Metallic bonding is the intermolecular force of attraction which exist between valence electrons and the metal atoms. It is considered as the sharing of various detached electrons between many positive ions, whereby the electrons serve as a "glue" which gives the substance a definite structure.

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Some one please help me ​
Norma-Jean [14]

Answer:

C.4

Explanation:

6 0
3 years ago
Nitrogen-13 has a half-life of about 10 minutes. How much of a 320g sample of N-13 would remain after 40 minutes?
lubasha [3.4K]

Answer:

The half-life of a radioisotope describes the amount of time it takes for said isotope to decay to one-half the original amount present in the sample.

Nitrogen-13, because it has a half-life of ten minutes, will experience two half-lives over the course of the twenty minute period. This means that 25% of the isotope will remain after this.

0.25 x 128mg = 32mg

32mg of Nitrogen-13 will remain after 20 minutes.

5 0
3 years ago
1.2 kg of aluminum at 20oC is added to 1.5 kg of water at 80oC. After the system reaches thermal equilibrium, what is its final
Lubov Fominskaja [6]

Answer:

The final temperature is 71.19 °C

Explanation:

Step 1: Data given

Mass of aluminium = 1.2 kg = 1200 grams

Temperature of aluminium = 20.0 °C

Specific heat of aluminium = 0.900 J/g°C

Mass of water = 1.5 kg = 1500 grams

Temperature of water = 80.0 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the final temperature

heat gained = heat lost

Q(aluminium) = - Q(water)

Q = m*c*ΔT

m(aluminium) * c(aluminium) * ΔT(aluminium) = - m(water) * c(water) * ΔT(water)

⇒ with mass of aluminium = 1200 grams

⇒ with specific heat of aluminium = 0.900 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 20.0 °C

⇒ with mass of water = 1500 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 80.0°C

1200 * 0.900 * (T2-20.0°C) = -1500 * 4.184 * (T2 - 80.0°C)

1080 * (T2 - 20.0°C) = -6276 * (T2 - 80.0°C)

1080 T2 - 21600 = -6276T2 + 502080

7356T2 = 523680

T2 = 71.19 °C

The final temperature is 71.19 °C

8 0
3 years ago
An object traveling around another object space is in blank
natali 33 [55]

Answer: An orbit is a regular, repeating path that one object in space takes around another one. An object in an orbit is called a satellite. A satellite can be natural, like Earth or the moon. Many planets have moons that orbit them

HOPE THIS HELPS

6 0
3 years ago
Scientists Hydia, Christian, and Trynatie took 100 frogs. They kept 50 of the frogs at 35 degrees C. They kept 50 of the frogs a
Usimov [2.4K]

Answer: Temperature was kept as an independent variable to observe the changes in the heart beat.

Explanation:

Independent variable can be defined as the variable which can be changed to induce change in an dependent variable which is the outcome of the experiment.

According to the given situation, the temperature in which the frogs were kept changed to observe the changes in the rate of heart functioning. So, the   temperature is the independent variable which changed before the experiment began.

4 0
2 years ago
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