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8090 [49]
4 years ago
6

A train of 150 m length is going toward north direction at a speed of 10 ms–1 and a parrot is flying towards south direction par

allel to the railway track with a speed of 5 ms–1. The time taken by the parrot to cross the train is equal to.?
Physics
2 answers:
zloy xaker [14]4 years ago
3 0

Answer:

10ms

Explanation:

The bird must travel the length of the train (150m), with a combined speed of 15m/s this means it will take 10s to cross an accumulated 150ms.

OlgaM077 [116]4 years ago
3 0

Answer:

The time taken by the parrot to cross the train is = 10 m/s

Explanation:

given:

A train of 150 m length is going toward north direction at a speed of 10 m/s

and a parrot is flying towards south direction parallel to the railway track with a speed of 5 m/s

find;

The time taken by the parrot to cross the train

<u>using the distance over speed relation formula t = d / v</u>

where:

v = velocity

d = distance

t = time

v = 10 m/s + 5 m/s = 15 m/s (combine velocity)

d = 150 m

t = ?

plugin values into the formula

t = <u>   150   </u>

         15

t = 10 m/s

therefore,

The time taken by the parrot to cross the train is = 10 m/s

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A 10 kg ball strikes a wall with a velocity of 3 m/s to the left. The ball bounces off with a velocity of 3 m/s to the right. If
lord [1]

Answer:

The force is 272.73 newtons

Explanation:

We're going to use impulse-momentum theorem that states impulse is the change on the linear momentum this is:

\overrightarrow{J}=\overrightarrow{p}_{f}-\overrightarrow{p}_{i} (1)

Impulse is also defined as average force times the time the force is applied:

\overrightarrow{J}=\overrightarrow{F}_{avg}(\varDelta t) (2)

By (2) on (1):

\overrightarrow{F}_{avg}(\varDelta t)= \overrightarrow{p}_{f}-\overrightarrow{p}_{i}

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Using (5) on (3):

\overrightarrow{F}_{avg}=\frac{-60\, \frac{mkg}{s}}{0.22s}

F_{avg}=272.73N

8 0
4 years ago
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