Mass percentage of sodium chloride(NaCl) in ocean waters = 3.5 %
That means 3.5 g sodium chloride(NaCl) is present for every 100 g of ocean water.
The given mass of sodium chloride(NaCl) is 45.8 g
Calculating the mass of ocean waters that would contain 45.8 g sodium chloride(NaCl):

= 1309 g ocean water
Therefore, 45.8 g sodium chloride is present in 1309 g ocean water.
1) 7.15 * 10^6
since the exponent of the scientific notation is positive, move 6 places to the right.
so, <em>7.15 * 10^6 = 7150000</em>
2) 3.03 * 10^-8
Since the exponent of the scientific notation is negative, move the decimal point 8 places to the left.
so,<em> 3.03 * 10^-8 = 0.0000000303</em>
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3)<em> </em>4.9 * 10^-1
since the exponent of the scientific notation is negative, move 1 decimal place to the left.
so,<em> 4.9 * 10^-1 = 0.49</em>
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4) 2.886 * 10^5
since the exponent of the scientific notation is positive, move 5 decimal places to the right.
so,<em> 2.886 * 10^5 = 288600</em>
this is a dilution equation where 50.0 mL of 1.50 M H₂SO₄ is taken and added to 200 mL of water.
c1v1 = c2v2
where c1 is concentration and v1 is volume of the concentrated solution
and c2 is concentration and v2 is volume of the diluted solution to be prepared
50.0 mL of 1.50 M H₂SO₄ is added to 200 mL of water so the final solution volume is - 200 + 50.0 = 250 mL
substituting these values in the formula
1.50 M x 50.0 mL = C x 250 mL
C = 0.300 M
concentration of the final solution is A) 0.300 M
<span>Fluorine ONLY form\s an ion with a -1 charge. The other three are metals, and metals for positively charged ions.</span>