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3 years ago

Solid solution of a metal or nonmetal dissolved in a metal

Chemistry

1 answer:

guajiro [1.7K]3 years ago

3 0

An alloy is the solid solution of a metal or non-metal dissolved in a metal.

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All generators need some source of energy to rotate the coil or magnets. True or False

Llana [10]

.energy mechanical needs it Answer:

Yes.

Explanation:

7 0

3 years ago

Convert 321 millimeters to picometers

pantera1 [17]

3.21e+11 is your answer for 321 millimeters in picometers. Hope this helps!

3 0

3 years ago

How many molecules are in 5.50 grams of AgNO3?

mixas84 [53]

Answer:

1.95*10²² molecules are in 5.50 grams of AgNO₃

Explanation:

Being the molar mass of the elements:

Ag: 107.87 g/mole
N: 14 g/mole
O: 16 g/mole

then the molar mass of the compound is:

AgNO₃: 107.87 g/mole + 14 g/mole + 3*16 g/mole= 169.87 g/mole

Then you can apply the following rule of three: if 169.87 grams of the compound are present in 1 mole, 5.50 grams will be present in how many moles?

$moles=\frac{5.50 grams*1 mole}{169.87 grams}$

moles= 0.0324

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

You can apply the following rule of three: if by definition of Avogadro's Number 1 mole of the substance contains 6.023 * 10²³ molecules, 0.0324 moles how many molecules will it have?

$molecules=\frac{0.0324 moles*6.023*10^{23} molecules}{1 mole}$

molecules=1.95*10²²

1.95*10²² molecules are in 5.50 grams of AgNO₃

3 0

3 years ago

Calculate the molarity of 139 grams of sucrose, C12H22O11, in 2.60 liters of solution.

Allisa [31]

Answer:

to calculate the molarity of the said sucrose,

firstly calculate the moles

which is = Molecular weight of C12H22O11 = 342g/mol

then

moles = 139/342

= 0.41 moles

to calculate Molarity now

Molarity= moles of the solute/volume of solution in liter

=0.41/2.60

=0.158M

Explanation:

4 0

3 years ago

In your own words list the rules for naming hydrocarbons and substituted hydrocarbons. Be detailed in listing all rules includin

Irina18 [472]

Answer :

The basic rules for naming of hydrocarbons are :

First select the longest possible carbon chain.

The longest possible carbon chain should include the carbons of double or triple bonds.

The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne.

The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.

The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.

If two or more similar alkyl groups are present in a compound, the prefixes di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.

8 0

3 years ago