Answer : The mass of sodium fluoride added should be 0.105 grams.
Explanation : Given,
The dissociation constant for HF = 
Concentration of HF (weak acid)= 0.0310 M
First we have to calculate the value of
.
The expression used for the calculation of
is,

Now put the value of
in this expression, we get:



Now we have to calculate the concentration of NaF.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[NaF]}{[HF]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BNaF%5D%7D%7B%5BHF%5D%7D)
Now put all the given values in this expression, we get:
![2.60=3.17+\log (\frac{[NaF]}{0.0310})](https://tex.z-dn.net/?f=2.60%3D3.17%2B%5Clog%20%28%5Cfrac%7B%5BNaF%5D%7D%7B0.0310%7D%29)
![[NaF]=0.00834M](https://tex.z-dn.net/?f=%5BNaF%5D%3D0.00834M)
Now we have to calculate the moles of NaF.

Now we have to calculate the mass of NaF.

Therefore, the mass of sodium fluoride added should be 0.105 grams.
Answer:
The sample will look expanded and occupy more space.
Explanation:
Since, the pressure is constant here, but the temperature is changed. Therefore, according to Charles' Law Volume is directly proportional to Temperature, provided the pressure is kept constant. Mathematically:
V1/T1 = V2/T2
V1 = (T1/T2)(V2)
V1 = (300 k/450 k)(V2)
<u>V1 = (0.67)V2</u>
The equation indicates that The fina volume of the gas V2 will be greater than the initial volume V1. <u>Thus, sample will look expanded and occupy more space than the previous state.</u>
Answer:
Kindly check the explanation section.
Explanation:
From the description given in the question above, that is '' H subscript f to the power of degree of the reaction" we have that the description matches what is known as the heat of formation of the reaction, ∆fH° where the 'f' is a subscript.
In order to determine the heat of formation of any of the species in the reaction, the heat of formation of the other species must be known and the value for the heat of reaction, ∆H(rxn) must also be known. Thus, heat of formation can be calculated by using the formula below;
∆H(rxn) = ∆fH°( products) - ∆fH°(reactants).
That is the heat of formation of products minus the heat of formation of the reaction g specie(s).
Say heat of formation for the species is known as N(g) = 472.435kj/mol, O(g) = 0kj/mol and NO = unknown, ∆H°(rxn) = −382.185 kj/mol.
−382.185 = x - 472.435kj/mol = 90.25 kJ/mol
Explanation:
In the extreme winters , the water inside pipes freeze, on freezing it's(water molecule) density decreases and volume increases and therefore, the ice then expands and pushes the water towards the faucet, causing high pressure buildup in the pipe and after a limit the pipe burst. This is what happened to the family in Ottawa, where winters are chilly.
The sea level would rise by some 50 meters.
Explanation:
If the earth's temperature increases by 3 degrees the north and south pole would experience the ice melt at high speed.
The life will get difficult on the plains.
The extinction of some species will happen.
The sea level would rise by 50 meters. The increased sea level will cause depletion of habitat from plants and animals.
The floods will occur, land erosion, soil for agriculture land will get contaminated with the salt.