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daser333 [38]
3 years ago
11

Which of the following processes releases heat? Evaporation Freezing Melting Sublimation . I know for sure it is not freezing.

Chemistry
2 answers:
Ivan3 years ago
6 0
Freezing  process  release  heat  that  is  the  process  is  exothermic . In  addition   condensation  process also  is  exothermic. When  substance  losses  heat  energy  the  attractive  force  between  atom    slow  down  and  hence reduces  their  mobility.Example  when   water  turn  to  a  ice  cubes  the  reaction  releases  heat  energy.
gayaneshka [121]3 years ago
4 0
<span>During freezing heat will be released. Normally we wont think like that ,but the reality is during freezing the heat get released. the liquid water will have more energy than the frozen water .so during this transition the energy of the water get released as the latent heat. Basically when we need to reduce the temperature ie. freezing a substance, the heat already absorbed in the substance should be released out of the substance.</span>
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What is the value for the reaction: N2(g) + 2 O2(g) --&gt; N2O4(g) in terms of K values from the reactions:
Valentin [98]

Answer : The correct expression will be:

K=(K_1)^2\times K_2

Explanation :

The chemical reactions are :

(1) \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightleftharpoons NO(g) K_1

(2) 2NO(g)+O_2(g)\rightleftharpoons N_2O_4(g) K_2

The final chemical reaction is :

N_2(g)+2O_2(g)\rightleftharpoons N_2O_4 K=?

Now we have to calculate the value of K for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

K=(K_1)^2\times K_2

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3 years ago
ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST
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b

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After standardizing a NaOH solution, you use it to titrate an HCl solution known to have a concentration of 0.203 M. You perform
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0.203 is the mean of the concentration of the HCl solution

Explanation:

You have 5 concentrations. The most appropiate result is the mean of those results. The mean is a statistical defined as the sum of each result divided by the total amount of results. For the results of the problem, the mean is:

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<h3>0.203 is the mean of the concentration of the HCl solution</h3>
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A 50.0g g sample of 16n decays to 12.5g in 14.4 seconds. What is its half life
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<span>t is time </span>
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<span>log (At) = log [ Ao x (1/2)^(t/HL) ] </span>
<span>log (At) = log Ao + log (1/2)^(t/HL) </span>
<span>log (At) = log Ao + (t/HL) x log (1/2) </span>

<span>( log At - log Ao) / log (1/2) = t / HL </span>
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