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3 years ago

Which of the following processes releases heat? Evaporation Freezing Melting Sublimation . I know for sure it is not freezing.

2 answers:

Ivan3 years ago

6 0

Freezing process release heat that is the process is exothermic . In addition condensation process also is exothermic. When substance losses heat energy the attractive force between atom slow down and hence reduces their mobility.Example when water turn to a ice cubes the reaction releases heat energy.

gayaneshka [121]3 years ago

4 0

<span>During freezing heat will be released. Normally we wont think like that ,but the reality is during freezing the heat get released. the liquid water will have more energy than the frozen water .so during this transition the energy of the water get released as the latent heat. Basically when we need to reduce the temperature ie. freezing a substance, the heat already absorbed in the substance should be released out of the substance.</span>

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Identify the variables in this hypothesis.

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3 years ago

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A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

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Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

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$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

$v_2=\frac{276}{299} \times 200 = 184.62 \; ml$

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

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2 years ago

Which compounds are classified as Arrhenius acids?

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Answer:The correct answer is option 4.

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$HA(aq)\rightarrow H^++A^-$

Arrhenius bases are those compounds which gives $OH^-$ ions when dissolved in their aqueous solution.

$BOH(aq)\rightarrow OH^-+B^+$

$HBr \& H_2SO_4$ are Arrhenius acids because they form $H^+$ ions in their respective aqueous solution.

$HBr(aq)\rightarrow H^++Br^-$

$H_2SO_4(aq)\rightarrow 2H^++SO_{4}^{2-}$

Hence, the correct answer is option 4.

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3 years ago

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Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding? everyth

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Sucrose and other simple sugars may dissolve in water because they are polar molecules with an unequal charge distribution. Water is also quite polar, capable of forming weak, temporary connections with other polar compounds.

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A solution's solute and solvent are two different types of substances that can dissolve one another. Different solvents have different levels of solubility for different solutes. For instance, sugar is far more soluble in water than salt. Even sugar, though, has a limit on how much may dissolve.

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11 months ago

What is the percent composition of dinotrogen pentoxide? With work shown please

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Answer:

%N = 25.94%

%O = 74.06%

Explanation:

Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅

We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g

Step 4: Calculate the percent composition of N₂O₅

We will use the following expression.

%Element = m(Element)/m(Compound) × 100%

%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%

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2 years ago