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irga5000 [103]
2 years ago
7

Which point is on the circle with center (-3,-1) that contains the point (1, 2)?

Mathematics
1 answer:
jasenka [17]2 years ago
5 0

Answer:

Any point that is 5 units from the center

Step-by-step explanation:

The given circle is centered at;

(-3,-1) and contains (1,2).

The radius is given by:

r =  \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

We substitute the point to get:

r =  \sqrt{(1- - 3)^2 +(2- - 1)^2}

r =  \sqrt{4^2 +3^2}

r =  \sqrt{25}  = 5

Therefore any point that is 5 units from the center lies on this circle.

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Assuming that your question is (x-1)(x+2) = [5(x-1)]/x-1

On the right side, the x-1's will cancel out, leaving you with (x-1)(x+2) = 5

expand the left side, giving you x^2 + x -2 = 5
which goes to x^2 +x -7 = 0
the possible values for x are 2.93 and -3.93. I don't think this was your question, so I'll do the other possible question that you might have been asking.

(x-1)(x+2) = 5(x-1)

divide by x-1 on both sides, leaving you with x+2=5
x+2=5
x=5-3
x=3
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12/11k÷4/3k

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