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dimulka [17.4K]
3 years ago
6

In the image of the billiard table below, a cue ball is about to be struck and pushed toward the other balls

Chemistry
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

c

Explanation:

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Genrish500 [490]
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4 years ago
How many moles of oxygen are needed for the complete combustion of 12.6 moles of acetylene?
soldi70 [24.7K]

The moles of oxygen required to completely react with 1-mole acetylene is 2.5 mol.

The moles of reactant and product in a chemical reaction to the whole number ratio is given by the stoichiometric coefficient of the balanced chemical equation.

8 0
2 years ago
How many moles of calcium chloride are needed to react completely with 6.2 moles of silver nitrate
Harlamova29_29 [7]

Answer:

3.1 mol

Step-by-step explanation:

The balanced equation is

CaCl₂ + 2AgNO₃ ⟶ Ca(NO₃)₂ + 2AgCl

You want to convert moles of AgNO₃ to moles of CaCl₂.

The molar ratio is 2 mol AgNO₃:1 mol CaCl₂

Moles of CaCl₂ = 6.2 mol AgNO₃ × (1 mol CaCl₂/2 mol AgNO₃)

Moles of CaCl₂ = 3.1 mol CaCl₂

The reaction will require 3.1 mol of CaCl₂.

8 0
3 years ago
In a desert ecosystem, coyotes and rattlesnakes both eat the same type of mouse as a primary part of their diets. Recently, coyo
Alex Ar [27]

Answer:

there primary food source will still be the same

Explanation:

they will still ear mice but coyotesmay eat Humans if they are close because once they see humans they think they will be killed its there protectiong

5 0
4 years ago
Please someone help meeeeee!!!
Lorico [155]

Answer:

1 = Q =  7315 j

2 =Q =  -21937.5 j

Explanation:

Given data:

Mass of water = 50 g

Initial temperature = 20°C

Final temperature = 55°C

Energy required to change the temperature = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 j/g.°C.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 55°C - 20°C

ΔT = 35°C

Q = 50 g× 4.18 j/g.°C×35°C

Q =  7315 j

Q 2:

Given data:

Mass of metal = 100 g

Initial temperature = 1000°C

Final temperature = 25°C

Energy released = ?

Specific heat capacity = 0.225 j/g.°C

Solution:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 25°C - 1000°C

ΔT = -975°C

Now we will put the values in formula.

Q = 100 g × 0.225 j/g.°C × -975°C

Q =  -21937.5 j

Negative sign show that energy is released.

7 0
3 years ago
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