3 years ago

Can anyone can answer practice problem exercise 6.5

Chemistry

2 answers:

NemiM [27]3 years ago

6 0

Answer: Add more information please! Thanks!

Explanation:

Anettt [7]3 years ago

4 0

The answer is: 62.498 g/mol

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Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g) K=0.042 The concentrations of the products at equilibrium are [PCl3]=0.18 M and

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<u>Answer:</u> The equilibrium concentration of $PCl_5$ is 1.285 M.

<u>Explanation:</u>

The chemical equation for the decomposition of phosphorus pentachloride follows:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

The expression for equilibrium constant is given as:

$K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}$

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The concentration of solid substances are taken to be 1. Thus, they do not appear in the equilibrium constant expression.

Putting values in above equation, we get:

$0.042=\frac{0.18\times 0.30}{[PCl_5]}$

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Hence, the equilibrium concentration of $PCl_5$ is 1.285 M.

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