Divide the percentages by the RAM and then divide by the smallest value, this will give a ratio of the elements in the compound. N =14, O=16
Nitrogen : Oxygen
36.84/14 : 63.16/16
2.5 : 3.9
Divide both values by the lowest, and try to find whole number ratios:
2.5/2.5 : 3.9/2.5
1 : 1.5
Since the ratio of oxygen to nitrogen is 1.5 : 1, we have to double it so that it become 3:2
The empirical formula would be N₂O₃
Sulfur would be the answer
