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alukav5142 [94]
2 years ago
14

A car traveling at 60km/h undergoes uniform acceleration at a rate of 2/ms^2 until is velocity reached 120km/h determine the dis

tance traveled and the time taken to make the distance
Physics
1 answer:
jenyasd209 [6]2 years ago
3 0

Explanation:

Given that,

Initial speed of a car, u = 60 km/h = 16.67 m/s

Acceleration, a = 2m/s²

Final speed, v = 120 km/h = 33.33 m/s

We need to find the distance traveled and the time taken to make the distance.

acceleration = rate of change of velocity

a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{33.33 -16.67 }{2}\\\\t=8.33\ s

let the distance be d.

d=\dfrac{v^2-u^2}{2a}\\\\d=\frac{33.33^{2}-16.67^{2}}{2(2)}\\\\d=208.25\ m

Hence, the distance traveled and the time taken to make the distance is 208.25 m and 8.33 seconds respectively.

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Ezra is pulling a sled, filled with snow, by pulling on a rope attached to the sled. The rope makes an angle θ with respect to t
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Answer:

Explanation:

Given

rope makes an angle of \theta

Mass of sled and snow is m

Normal Force =F_N

applied Force is F

as Force is pulling in nature therefore normal reaction is given by

F_N=mg-F\sin \theta

Also F\cos \theta =f_r

f_r=\mu _k\cdot F_N

f_r=\mu _k\cdot (mg-F\sin \theta )

F\cos \theta =\mu _kF_N-------1

F\sin \theta =mg-F_N---------2

Squaring 1 & 2 and then adding

F^2=(\mu _kF_N)^2+(mg-F_N)^2

F=\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}

Substitute value of F in 1

cos\theta =\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}}

\theta =cos^{-1}(\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}})

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2 years ago
How are particles in liquids, solids, and gases the same? How are they different?
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Answer:

Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

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An elephant kicks a 2.5 kg rock that is initially at rest. The
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0.20Answer:

Explanation:

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two electrons are an angstrom (1x10^-10m) apart. What electrostatic force do they exert on one another?
Irina-Kira [14]

Answer:

2.30 × 10⁻⁸ N if the two electrons are in a vacuum.

Explanation:

The Coulomb's Law gives the size of the electrostatic force F between two charged objects:

\displaystyle F = -\frac{k\cdot q_1 \cdot q_2}{r^{2}},

where

  • k is coulomb's constant. k = 8.99\times 10^{8}\;\text{N}\cdot\text{m}^{2}\cdot\text{C}^{-2} in vacuum.
  • q_1 and q_2 are the signed charge of the objects.
  • r is the distance between the two objects.

For the two electrons:

  • q_1 = q_2 = 1.60\times 10^{-19}\;\text{C}.
  • r = 1\times 10^{-10}\;\text{m}.
  • \displaystyle F = -\frac{k\cdot q_1 \cdot q_2}{r^{2}} = -\frac{8.99\times 10^{8}\times (1.60\times 10^{-19})^{2}}{(1\times 10^{-10})^{2}} = 2.30\times 10^{-8}\;\text{N}.

The sign of F is negative. In other words, the two electrons repel each other since the signs of their charges are the same.

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Savanna regions developed during the Triassic period. true or false
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Savanna regions developed during the Triassic period. is true
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