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otez555 [7]
3 years ago
10

Find the product. 7,263 times 27

Mathematics
1 answer:
Dominik [7]3 years ago
8 0

the answer is: 196101

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Solve the inequality.<br> - 16 - 4x _&lt;0<br> The solution is x
Scrat [10]

Answer:

the answer for will be x≥-4

5 0
3 years ago
Can anyone answer this pls!!!!!!!!!!
gizmo_the_mogwai [7]

u₁₂ represents the amount of loan remaining after 12 years

<h3>How to interpret u₁₂?</h3>

The function is given as:

u₀ = 8000

u_n = u_{n-1}(1 + 0.054) - 500

Given that the subscript n in u_n represents number of years and u_n represents the amount left to be paid after n years.

We can conclude that:

u₁₂ represents the amount of loan remaining after 12 years

Read more about loan at
brainly.com/question/26011426

#SPJ1

6 0
1 year ago
WILL GIVE BRAINLIEST! NEED QUICK HELP ASAP! Photo added! least common denominator x^3/x^2+4x+4 and -9/x^2+5x+6
Oksanka [162]

The denominator( s ) we are given are x^2 + 4x + 4, and . The first thing we want to do is factor the expressions, to make this easier -

x^2 + 4x + 4

This expression is a perfect square, as ( x )^2 = x^2, ( 2 )^2 = 4, 2 * ( x ) * ( 2 ) = 4x. Thus, the simplified expression should be the following -

( x + 2 )^2

The other expression is, on the other hand, not a perfect square so we must break this expression into groups and attempt factorization -

x^2 + 5x + 6,\\\left(x^2+2x\right)+\left(3x+6\right),\\x\left(x+2\right)+3\left(x+2\right),\\\left(x+2\right)\left(x+3\right)\\\\Factored Expression = \left(x+2\right)\left(x+3\right)

Combining ( x + 2 )^2 and ( x + 2 )( x + 3 ), the expression that contains factors of each is ( x + 2 )^2 * ( x + 3 ), or in other words the LCM.

<u><em>Solution = </em></u>\left(x+2\right)^2\left(x+3\right)<u><em /></u>

3 0
3 years ago
Select all the expressions that show the distance between points A and B.
qwelly [4]

Answer:

0 -1-(-8)

0-1=-1

-1-(-8)

-1+8

=7

7 0
3 years ago
Name The postulate or theorem you can use to prove the triangles congruent
Zielflug [23.3K]
The answer is HL. HL is a theorem stating that if the hypotenuse and one leg are congruent to another pair of hypotenuse and leg then the triangles themselves are congruent. Hope this helps. 
8 0
3 years ago
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