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3 years ago

State how many mole ratios can be written for a reaction involving three substances.

1 answer:

6 0

It's one ratio per substance so say if you had N2 + 3H2 > 2NH3 (chemical equation for the synthesis of ammonia) just look at the number coefficients(for 3H2 the coefficient would be 3 and for 2NH3 the coefficient would be 2 and so on)So it would take 1mole of nitrogen to react with 3 moles of hydrogen In order to produce 2 moles of ammonia so there would be 6 ratios you could write comparing two substances at a time In a reaction involving 3 substances ^^; hope this helps somewhat ^^;

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What sequence should be followed when conducting a laboratory investigation? Make observations, gather experimental data, form a

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Answer:

Define a problem, form a hypothesis, gather experimental data, form a conclusion

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3 years ago

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What is the change in internal energy (ΔΕ) of a system when 5 kJ of work is done on the system while it releases 13 kJ of energy

meriva

The change in internal energy (ΔΕ) of a system : -8 kJ

<h3>Further explanation </h3>

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created

The equation is:

$\tt \Delta U=Q+W$

Energy owned by the system is expressed as internal energy (U)

This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)

The sign rules for heat and work are set as follows:

• The system receives heat, Q +

• The system releases heat, Q -

• The system does work, W -

• the system accepts work, W +

5 kJ of work is done on the system : W = +5 kJ

releases 13 kJ of energy to the surroundings : Q = -13 kJ

$\tt \Delta E=-13+5=-8~kJ$

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2 years ago

Pls help me I don’t know what to dooooo

Ivan

Molarity = moles of solute/volume of solution in liters.

The solute here is NaCl, of which we have 46.5 g. To calculate the molarity of an NaCl solution, we need to know the number of moles of NaCl. To convert from grams to moles, we divide the mass by the molar mass of NaCl. The molar mass of NaCl is the sum of the atomic masses of Na and Cl: 23 amu + 35 amu = 58 amu. For our purposes, we can regard amu as equivalent to grams/mole.

(46.5 g)/(58 g/mol) = 0.8017 moles NaCl.

Now that we know both the number of moles of our NaCl solute and the volume of the solution, we can calculate the molarity:

(0.8017 moles NaCl)/(2.2 L) = 0.364 M.

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