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Natalka [10]
4 years ago
12

A ball is thrown horizontally from the top of a 41 m vertical cliff and lands 112 m from the base of the cliff. How fast is the

ball thrown horizontally from the top of the cliff?
Physics
1 answer:
yanalaym [24]4 years ago
4 0

Answer:

4.78 second

Explanation:

given data

vertical cliff = 41 m

height = 112 m

solution

we know here time taken to fall vertically from the cliff =  time taken to move horizontally   ..........................1

so we use here vertical component of ball

and that is accelerated motion with initial velocity = 0

so we can solve for it as

height = 0.5 ×  g ×  t²     ........................2

put here value

112 = 0.5 ×  9.8 ×  t²    

solve it we get

t²   = 22.857

t = 4.78 second

ball thrown horizontally from the top of the cliff in 4.78 second

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Answer:

The x component of the electric field at y=2m is E_{x}=17.97\frac{N}{C}

Explanation:

For a linear charge, using <u>Gauss Law</u>, we get that the <em>Electric field (radial) has the following form</em>

E=\frac{\lambda}{2\pi\epsilon_{0}r}

<em>where λ is the charge for longitud unit given in the problem, r is replaced by the y coordinate, and there are two known more data</em>. So

E=\frac{2*10x^{-9}}{2*2\pi\epsilon_{0}}=17.97\frac{N}{C}

is the x component of the Electric field at y=2m on the y axis, which is what we wanted to know.

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3 years ago
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A small 1.0 kg steel ball rolls west at 3.0 m/s collides with a large 3.0 kg ball at rest. After the collision, the small ball m
77julia77 [94]

Answer:

The direction of the momentum of the large ball after the collision with respect to east is 146.58°.

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Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

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v_{2}=-i+0.66j

The direction of the momentum

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7 0
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Answer:

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7 0
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1s = 1.0 \times  {10}^{ - 24} s \:  \: = 1ys
1 ys is the smallest unit of time.
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