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STALIN [3.7K]
4 years ago
10

If you walk North for 40 feet and then walk East for 30 feet, what is your total distance

Physics
1 answer:
yarga [219]4 years ago
5 0

Answer:

The person travelled a total distance of (40+30) feet = 70 feet

Displacement= 50feet (im not positive on the displancement)

displacemeny is the shortest distance between two pionts

Explanation:

You might be interested in
Cual es la energía cinética de un objeto cuya masa es de 2kg y se mueve a una velocidad de 5 m/s2 * a)10 J b)25 J c)50J d)98J
Advocard [28]
Let the mass be m
v = 5m/s
K.E = 25 J
K.E = 1/2 mv^2
25 = 1/2 m (5)^2
25 x 2 = 25m
m = 2 kg
Now if the velocity becomes 3 times then the velocity is 3 x 5 = 15m/S
Now new K.E = 1/2 x 2 x 15^2
= 225 J
7 0
3 years ago
The Moon is attracted to the Earth. The mass of the Earth is 6.0x1024 kg and the mass of the Moon is 7.4x1022 kg. If the Earth a
xxTIMURxx [149]

Sorry I don't know the answer

7 0
3 years ago
how many miles can you get on one tank of gas if yout tank holds 18 gallons and you get 22miles per gallon
yaroslaw [1]
Well to find the total miles what I would do is 18 x 22 which would equal 396 so the answer would be: You can go 396mi with a car that gets 22 mpg* and holds 18 gallons

*Mpg=Miles per gallon

8 0
4 years ago
An inductive circuit contains resistance of 20 ohm and an inductance of 20 H. If an ac voltage of 120 V and frequency 60 Hz is a
elena-s [515]

Answer:

answer : option (b) 0.016 amp

explanation : resistance of resistor , R = 10 Ω

inductance of inductor , X_LX

L

= 20H

voltage of AC circuit , V = 120volts

frequency, ff =60Hz

so, angular frequency, \omega=2\pi fω=2πf = 2 × π × 60 = 120π rad/s

now, current , i=\frac{V}{\sqrt{R^2+\omega^2L^2}}i=

R

2

+ω

2

L

2

V

= 120/√{10² + (120π)² × 20²}

= 120/√{100 + 14400π² × 400}

after solving this we get, i = 0.016 amp

8 0
3 years ago
Based on the data collected, explain why a launch angle of 30 degrees (HIGH HORIZONTAL VELOCITY & SMALL TIME OF FLIGHT) will
Gennadij [26K]

Answer:

Explanation:

The horizontal distance traveled by the projectile is given by the formula

R=\frac{u^{2}Sin2\theta }{g}

The formula for the time of flight is given by

T = \frac{2u Sin\theta }{g}

Case I: when the launch angle is 30°

So, R_{1}=\frac{u^{2}Sin60 }{g}

R_{1}=\frac{0.866u^{2}}{g}

Horizontal velocity = u Cos 30 = 0.866 u

T_{1} = \frac{2u Sin30 }{g}=\frac{u}{g}

Case II: when the launch angle is 60°

R_{2}=\frac{u^{2}Sin120}{g}

R_{2}=\frac{0.866u^{2}}{g}

Horizontal velocity = u Cos 60 = 0.5 u

T_{1} = \frac{2u Sin60 }{g}=\frac{1.73 u}{g}

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

5 0
3 years ago
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