Answer:
12000 miles per hour
Explanation:
If skid Marx went from zero to 10 miles in 3 seconds the his speed would have been 12000 miles per hour.
Answer:
432 units
Explanation:
Let the charges be q and Q separated by a distance r. The electrostatic force , F = kqQ/r² = 72 units. If q = 2q and Q = 3Q, then the new electrostatic force is
F = k × 2q × 3Q/r² = 6kqQ/r² = 6 × 72 = 432 units
Measure the length of one side and then cube the answer. So if x represents the measurement of one side, x³ will give you the volume.
-- <u><em>Current is measured in amps.</em></u> (You can use any symbol you want to represent current, but the most common one is " I ", not "Δ".)
-- <u><em>The relationship between current, voltage, and resistance is mathematically defined by Ohm's Law. </em></u>
-- <u><em>Current is the flow of electrons through a circuit.</em></u>
-- (Ohm's Law is NOT mathematically represented by the equation V=I/R.) <u><em>It should be V = I · R</em></u> .
(When solving for Resistance in a circuit and both voltage and current are known values, the equation I =V*R is not true, and not the way to solve it.) <u><em>If the resistance is what you're looking for, then the equation to use is </em></u><u><em>R = V / I</em></u><u><em> . </em></u>
<em>-- </em><u><em>If the voltage in a circuit is increased, the current will also increase.</em></u>
Answer:
Q₁ = Q₂ = 8.84 x 10⁻⁹ C
Explanation:
given,
mass of ball, m = 0.16 g = 1.6 x 10⁻⁴ Kg
ball each other, r = 6.8 cm
Weight of the ball
F_w = m g
F_w = 1.6 x 10⁻⁴ x 9.8
F_w = 1.56 x 10⁻³ N
The tension in each string is a force directed along the length of the string and is the hypotenuse of a right triangle.
we have to find the horizontal component of the forces.
The length of the string,L is 35 cm so, it will be the hypotenuse.
θ be the angle made with imaginary vertical line and the string.
now,
θ = 5.57°
horizontal component of the force = ?
vertical component of force,F_v = 1.56 x 10⁻³ N


F_h = 1.52 x 10⁻⁴ N
now, each ball will be repelled by
F = 1.52 x 10⁻⁴ N
now calculation of charges

Q₁ = Q₂ because both charge are same

Q² = 7.809 x 10⁻¹⁷
Q = 8.84 x 10⁻⁹ C
hence the change on the balls were Q₁ = Q₂ = 8.84 x 10⁻⁹ C