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poizon [28]
4 years ago
15

Use Lagrange multiplier techniques to find the local extreme values of the given function subject to the stated constraint. If a

ppropriate, determine if the extrema are global. (If a local or global extreme value does not exist enter DNE.) f(x, y)

Engineering
1 answer:
Leno4ka [110]4 years ago
5 0

Answer:

Explanation:

Given f(x, y) = 5x + y + 2 and g(x, y) = xy = 1

The step by step calculation and appropriate substitution is clearly shown in the attached file.

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A room is filled with saturated moist air at 25°C and a total pressure of 100 kPa. If the mass of dry air in the room is 100 kg,
ANTONII [103]

Answer:the mass of water vapor is=d. 2.04 kg

Explanation:

The humidity ratio by mass is given as

x = mw / ma                                  (1)

where

mw = mass of water vapor

ma = mass of dry air

And also humidity ratio by pressure by  Ideal Gas Law is given as

x = 0.62198 pw / (pa - pw)                            (2)

where

pw = partial pressure of water vapor in moist air

pa = atmospheric pressure of moist air

Equating both equation we have that

Humidity ratio =  0.62198 pw / (pa - pw)= mw / ma      (3)

From the from the water table at 25°C,

water vapor partial pressure = 23.8 torr

 1 atm =760 torr.

1 atm = 101.325 kPa,

So, 760 torr =101.325 kPa,

Therefore 23.8 torr =3.173kPa

Humidity ratio =  0.62198 pw / (pa - pw)= mw / ma  

0.62198 x 3.173 / (100-3.173)= mw / 100

1.9736 /96.827=mw/100

0.0204=mw/100

mw=2.04kg

6 0
4 years ago
When the pressure relief valve in a system opens during work
Olegator [25]

Answer:

The relief valve will open as pressure caused by a downstream load or backpressure increases high enough to force the poppet or spool open against its spring.

Explanation:

6 0
2 years ago
Cyborgs are defined by which of the following?
Snezhnost [94]

Answer:

Enhanced mechanical parts. im not use tho

hope this helps

have a good day :)

Explanation:

7 0
3 years ago
Gear A has a mass of 1 kg and a radius of gyration of 30 mm; gear B has a mass of 4 kg and a radius of gyration of 75 mm; gear C
Kruka [31]

Answer:

(4.5125 * 10^-3 kg.m^2)ω_A^2

Explanation:

solution:

Moments of inertia:

I = mk^2

Gear A: I_A = (1)(0.030 m)^2 = 0.9*10^-3 kg.m^2

Gear B: I_B = (4)(0.075 m)^2 = 22.5*10^-3 kg.m^2

Gear C: I_C = (9)(0.100 m)^2 = 90*10^-3 kg.m^2

Let r_A be the radius of gear A, r_1 the outer radius of gear B, r_2 the inner radius of gear B, and r_C the radius of gear C.

r_A=50 mm

r_1 =100 mm

r_2 =50 mm

r_C=150 mm

At the contact point between gears A and B,

r_1*ω_b = r_A*ω_A

ω_b = r_A/r_1*ω_A

       = 0.5ω_A

At the contact point between gear B and C.

At the contact point between gears A and B,

r_C*ω_C = r_2*ω_B

ω_C = r_2/r_C*ω_B

       = 0.1667ω_A

kinetic energy T = 1/2*I_A*ω_A^2+1/2*I_B*ω_B^2+1/2*I_C*ω_C^2

                           =(4.5125 * 10^-3 kg.m^2)ω_A^2

6 0
4 years ago
What is compression ratio of an Otto cycle? How does it affect the thermal efficiency of the cycle?
GuDViN [60]

Answer:

r= \dfrac{V_1}{V_2}

\eta =1-\dfrac{1}{r^{\gamma-1}}

Explanation:

Compression ratio:

   Compression ratio is the ratio of volume in the cylinder.Generally it is denoted by r.

The compression ratio for Otto cycle is about 8 to 12.But the compression ratio of diesel engine is about 14 to 25.

So from the Otto cycle compression ratio can be define as

r= \dfrac{V_1}{V_2}

As we know that efficiency defines as the ratio of work out to the heat input.In the Otto cycle the efficiency is given as in terms of compression ratio r as

\eta =1-\dfrac{1}{r^{\gamma-1}}

Where γ is the heat capacity ratio.

6 0
3 years ago
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