Answer:
Explanation:
Compression ratio:
Compression ratio is the ratio of volume in the cylinder.Generally it is denoted by r.
The compression ratio for Otto cycle is about 8 to 12.But the compression ratio of diesel engine is about 14 to 25.
So from the Otto cycle compression ratio can be define as
As we know that efficiency defines as the ratio of work out to the heat input.In the Otto cycle the efficiency is given as in terms of compression ratio r as
Where γ is the heat capacity ratio.
Answer:
Minimum electrical power required = 3.784 Watts
Minimum battery size needed = 3.03 Amp-hr
Explanation:
Temperature of the beverages,
Outside temperature,
rate of insulation,
To get the minimum electrical power required, use the relation below:
V = 5 V
Power = IV
If the cooler is supposed to work for 4 hours, t = 4 hours
Minimum battery size needed = 3.03 Amp-hr
Answer:
Explanation:
From the question we are told that:
Initial Pressure
Initial Temperature
Final Pressure
Final Temperature
Work Output
Generally Specific Energy from table is
At initial state
With
Specific Volume
At Final state
Generally the equation for The Process is mathematically given by
Assuming Mass to be Equal
Where
Therefore
Answer:
a.)
US Sieve no. % finer (C₅ )
4 100
10 95.61
20 82.98
40 61.50
60 42.08
100 20.19
200 6.3
Pan 0
b.) D10 = 0.12, D30 = 0.22, and D60 = 0.4
c.) Cu = 3.33
d.) Cc = 1
Explanation:
As given ,
US Sieve no. Mass of soil retained (C₂ )
4 0
10 18.5
20 53.2
40 90.5
60 81.8
100 92.2
200 58.5
Pan 26.5
Now,
Total weight of the soil = w = 0 + 18.5 + 53.2 + 90.5 + 81.8 + 92.2 + 58.5 + 26.5 = 421.2 g
⇒ w = 421.2 g
As we know that ,
% Retained = C₃ = C₂×
∴ we get
US Sieve no. % retained (C₃ ) Cummulative % retained (C₄)
4 0 0
10 4.39 4.39
20 12.63 17.02
40 21.48 38.50
60 19.42 57.92
100 21.89 79.81
200 13.89 93.70
Pan 6.30 100
Now,
% finer = C₅ = 100 - C₄
∴ we get
US Sieve no. Cummulative % retained (C₄) % finer (C₅ )
4 0 100
10 4.39 95.61
20 17.02 82.98
40 38.50 61.50
60 57.92 42.08
100 79.81 20.19
200 93.70 6.3
Pan 100 0
The grain-size distribution is :
b.)
From the diagram , we can see that
D10 = 0.12
D30 = 0.22
D60 = 0.12
c.)
Uniformity Coefficient = Cu =
⇒ Cu =
d.)
Coefficient of Graduation = Cc =
⇒ Cc = = 1
Answer: hello attached below is the missing image the slender weight is different from what is in the question here so I worked with 23-Ib as requested in the question
answer
≈ 12.17 Rad/sec
Explanation:
weight of bullet ( Wb ) = 0.08 Ib
horizontal velocity = 1800 ft/s
Slender(Wr) = 23-Ib bar with
length ( L ) = 30
h = 12 inches
Vro = 0
<u>Calculate the angular velocity of the bar immediately after the bullet becomes embedded </u>
attached below is a detailed solution
6.708 = ( 0.05011 + 0.5011 ) w'
w' = 6.708 / 0.55121 ≈ 12.17 Rad/sec
