Question

A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?
A.) 35 feet
B.) 40 feet
C.) 42 feet
D.) 45 feet

Answer 1

To answer the question, directly substitute the value given for t to the given function of height.
                     h = -16t² + 60t + 6
                     h = (-16)(3 s)² + (60)(3) + 6 = 42
Therefore, the height of the ball after 3 seconds is 42 ft.