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Alexus [3.1K]
3 years ago
12

A thermometer is placed in water in order to measure the water’s temperature. What would cause the liquid in the thermometer to

rise?
Physics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

B - The molecules in the thermometer’s liquid spread apart.

Explanation:

on edge 2020

oksano4ka [1.4K]3 years ago
5 0
The only thing that makes the liquid of the thermometer rises up is that the temperature of the water is higher than the temperature of the liquid of the thermometer and a heat transfer process takes place from the water to the liquid of the thermometer by convection. 
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Sounds travels in a ____ wave A. Transverse B. Compressional C. Surface D. Inverted
MissTica

Answer: A. Transverse

Explanation:

Sound is a mechanical transverse wave, it travels faster in solids than in liquids or gases. This is because the speed of the mechanical waves is determined by a relationship between the elastic properties of the medium in which they are propagated and the mass per unit volume of the medium.  

 

In addition, the speed of sound varies with changes in the temperature of the medium. This is because an increase in temperature means that the frequency of interactions between the particles that transport the vibration increases, hence this increase in activity increases the speed.

Hence:

<h3>Sounds travels in a <u>transverse</u> wave</h3>
7 0
3 years ago
A(n) 71.1 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 70.2 m away from the shuttle
denpristay [2]

Answer:

10.347 minutes.

Explanation:

According to F = ma, she exerts force on camera of the magnitude

F = 0.67Kg*12m/s^{2} = 8.04N, assuming it took her one second to accelerate camera to 12m/s, then by newtons third law, which says every action has equal and opposite reaction , the camera exerts the same amount of force on the astronaut which gives her acceleration of a = \frac{8.04N}{70.2Kg} = 0.1130801680m/s^2.

and velocity of V = 0.1130801680m/s.

at this velocity , the astronaut has to cover the distance of 70.2 meters, it will take her 620.7985075s = 10.347 min to get to the shuttle (using S = vt).

4 0
3 years ago
The rocky planets are made of material that is much (mire/less) dense than the outer planets.​
IRINA_888 [86]

The outer planets (Jupiter, Saturn, Uranus, Neptune) are called the "<u>GAS</u> giants".

The rocky planets are called "rocky" because they're made of <u>ROCK</u>.

Does this help guide you to the correct choice ?

Here's another hint:  The MOST dense planet in our solar system, the one we call "Earth", is one of the 'rocky planets'.

7 0
3 years ago
A photoelectric effect experiment finds a stopping potential of 1.93 V when light of wavelength 200 nm is used to illuminate the
GenaCL600 [577]

a) Zinc (work function: 4.3 eV)

The equation for the photoelectric effect is:

E=\phi + K (1)

where

E=\frac{hc}{\lambda} is the energy of the incident photon, with

h = Planck constant

c = speed of light

\lambda = wavelength

\phi = work function of the metal

K = maximum kinetic energy of the photoelectrons emitted

The stopping potential (V) is the potential needed to stop the photoelectrons with maximum kinetic energy: so, the corresponding electric potential energy must be equal to the maximum kinetic energy,

eV=K

So we can rewrite (1) as

E=\phi + eV

where we have:

\lambda=200 nm = 2\cdot 10^{-7} m

V = 1.93 V

e is the electron charge

First of all, let's find the energy of the incident photon:

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2\cdot 10^{-7}m}=9.95\cdot 10^{-19} J

Converting into electronvolts,

E=\frac{9.95\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=6.22 eV

And now we can solve eq.(1) to find the work function of the metal:

\phi = E-eV=6.22 eV-1.93 eV=4.29 eV

so, the metal is most likely zinc, which has a work function of 4.3 eV.

b) The stopping potential is still 1.93 V

Explanation:

The intensity of the incident light is proportional to the number of photons hitting the surface of the metal. However, the energy of the photons depends only on their frequency, so it does not depend on the intensity of the light. This means that the term E in eq.(1) does not change.

Moreover, the work function of the metal is also constant, since it depends only on the properties of the material: so \phi is also constant in the equation. As a result, the term (eV) must also be constant, and therefore V, the stopping potential, is constant as well.

6 0
3 years ago
What is your hypothesis (or hypotheses) for this experiment?
mariarad [96]

Answer:

mr or ms please type ur question fully please

7 0
3 years ago
Read 2 more answers
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