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Alexus [3.1K]
3 years ago
12

A thermometer is placed in water in order to measure the water’s temperature. What would cause the liquid in the thermometer to

rise?
Physics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

B - The molecules in the thermometer’s liquid spread apart.

Explanation:

on edge 2020

oksano4ka [1.4K]3 years ago
5 0
The only thing that makes the liquid of the thermometer rises up is that the temperature of the water is higher than the temperature of the liquid of the thermometer and a heat transfer process takes place from the water to the liquid of the thermometer by convection. 
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Why is the use of wood as a fuel not advisable the forests can be replenished​
earnstyle [38]

Answer:

because of carbon content in wood harms environment , although forest can be replenished but no one wanted to plant a tree in his/ her home. And also, cutting of woods causes environmental imbalances. Further, burning of wood causes a lot of pollution. Hence, it is advisable not to use wood as a fuel.

Explanation:

5 0
2 years ago
How to calculate average breaking force physics
Alexandra [31]

Answer:

Formula: Remove the zero from the speed, multiply the figure by itself and then multiply by 0.4. The figure 0.4 is taken from the fact that the braking distance from 10 km/h in dry road conditions is approximately 0.4 metres.

8 0
3 years ago
Calculate the average atomic mass of element, X. A sample of X is 65.20% X-17, 13.50% X-18, and 21.30% X-19.
k0ka [10]

Answer:

The average atomic mass of element X is 17.561 u.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i .....(1)

We are given:

Mass of isotope X-17 = 17 u

Percentage abundance of isotope X-17 = 65.20 %

Fractional abundance of isotope 1 = 0.6520

Mass of isotope X-18 = 18 u

Percentage abundance of isotope X-18 = 13.50 %

Fractional abundance of isotope X-18 = 0.1350

Mass of isotope X-19 = 19 u

Percentage abundance of isotope X-19 =21.30%

Fractional abundance of isotope X-19 = 0.2130

Putting values in equation 1, we get:

\text{Average atomic mass of Z}=\sum[(17 u\times0.6520 )+(18 u\times 0.1350)+(19 u\times 0.2130)]

\text{Average atomic mass of Z}=17.561 u

6 0
3 years ago
Please help. I need help with the questions on this page.
DaniilM [7]
Try looking up facts about physics or referring back to your notes in class. :)
6025loveteal
4 0
3 years ago
How long will the energy in a 1470-kJ (350-kcal) cup of yogurt last in a woman doing work at the rate of 150 W with an efficienc
Lyrx [107]

Answer:

The 1470 kJ of energy supplied by the yogurt would be consumed by 150 W of work (efficiency of 20%) in about 32.7 h. Then if people is not careful, easily would have more energy from the food that the amount that can consume exercising.

Explanation:

Step 1.

  • Energy supplied: 1470 kJ = 1470000 J.
  • Rate of energy used for the : 150 W = 150 J/s. <em>This means that each second of this kind of work requieres 150 J of energy,</em>

Step 2

For this case, efficiency is defined as the relationship between the actual rate of energy used, to the rate of energy consumed to obtain it. So:

Eficiency=\frac{E_{obtain} }{E_{consumed} } \\

Then the rate of energy required for this work, is calculated solving for E_{Consumed}:

E_{consumed} =\frac{E_{obtain}}{Efficiency} =\frac{150\frac{J}{s} }{0.20} =750\frac{J}{s}

<em>This means that for a work that as a rate of 150 J/s , It requieres to consume energy at a rate of 750 J/s.</em>

Step 3

Now, it is possible to calculate how much time would be needed to consume the 1470000 J of energy of the yogurt. It done using this relationship:

Time=\frac{Energy}{rate}

Where Energy stands for the total amount of energy that would be consumed, and rate stans for the rate of energy consumption, Then the time would be:

Time=\frac{1470000J}{750\frac{J}{s} }=1960s=32.7 h

Then if for the consumption of 1470 kJ of energy is required almost 33 hours, Then is easy to see that the amount of enegy that can be obtain of food would much more than the amount that can be depleted by exercise

5 0
3 years ago
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