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ruslelena [56]
3 years ago
9

A 0.300 m solution of hcl is prepared by adding some 1.50 m hcl to a 500 ml volumetric flask and diluting to the mark with deion

ized water. what volume of 1.50 m hcl must be added?
Chemistry
1 answer:
liberstina [14]3 years ago
8 0
In dilution we add distilled water to decrease the concentration of required sample from high concentration to lower concentration
The law used for dilution:
M₁V₁]Before dilution = M₂V₂] After dilution
M₁ = 1.5 M
V₁ = ?
M₂ = 0.3 M
V₂ = 500 ml
1.5 * V₁ = 0.3 * 500 ml
so V₁ = 100 ml and it completed to 500 ml using 400 ml deionized water
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Oxygen is composed of three isotopes: oxygen-16, oxygen-17 and oxygen-18 and has an average atomic mass of 15.9982 amu. Oxygen-1
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Answer:

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Explanation:

The average atomic mass of oxygen is given by:

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Where:

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%: is the percent abundance

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Hence, the percent abundance of O-18 is:  

m_{O} = m_{^{16}O}*\%_{16} + m_{^{17}O}*\%_{17} + m_{^{18}O}*\%_{18}  

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x = 0.980614 \times 100 = 98.0614 \%                                                              

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\%_{18} = (1 - 3.2 \cdot 10^{-4} - 0.980614) \times 100 = 1.9066 \%                      

Therefore, the percent abundance of oxygen-18 is 1.9066%.

I hope it helps you!                                                      

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Explanation:

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