A 1056-hertz tuning fork is struck at the same time as a note on the piano and you hear 2 beats/second. You tighten the piano st
1 answer:
Answer:
The frequency of the piano string is <em>1059 Hz</em>.
Explanation:
The frequency beat (fb), 2 beats/second, is the absolute difference between the frequency of the tuning fork (1056 Hz) and the frequency of the piano string.
As the piano string gets tightened, the frequency beat becomes 3 beats/second.
Therefore,
fb =
You might be interested in
<h2>10.5</h2><h3>remember pemdas</h3>
- parentheses
- exponents <em>excluded for this problem</em>
- multiplication
- division
- addition
- subtraction
- parentheses
1 × 3 = 3
<h3>step 3. find 36 divided by 2</h3>36 ÷ 2 = 18
<h3>step 4. add the values together</h3>18 + 3 = 21
<h3>step 5. find 14 times 3</h3>14 × 3 = 42 <em>you can also do 7 × 6 and will get the same result because 7 is half of 14 and 3 is half of 6</em>
<h3>step 6. add what is outside the parentheses</h3>21 + 42 = 63
<h3>step 7. divide by 6</h3>63 ÷ 6 = 10.5 10 remainder of 3 <em>remainder means left over</em>
<em />