A 1056-hertz tuning fork is struck at the same time as a note on the piano and you hear 2 beats/second. You tighten the piano st
1 answer:
Answer:
The frequency of the piano string is <em>1059 Hz</em>.
Explanation:
The frequency beat (fb), 2 beats/second, is the absolute difference between the frequency of the tuning fork (1056 Hz) and the frequency of the piano string.
As the piano string gets tightened, the frequency beat becomes 3 beats/second.
Therefore,
fb =
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(BELOW YOU CAN FIND ATTACHED THE IMAGE OF THE SITUATION)
Answer:
Explanation:
For this we're going to use conservation of mechanical energy because there are nor dissipative forces as friction. So, the change on mechanical energy (E) should be zero, that means:
(1)
With the initial kinetic energy,
the initial potential energy,
the final kinetic energy and
the final potential energy. Note that initialy the masses are at rest so
, when they are released the block 2 moves downward because m2>m1 and finally when the mass 2 reaches its maximum displacement the blocks will be instantly at rest so
. So, equation (1) becomes:
(2)
At initial moment all the potential energy is gravitational because the spring is not stretched so and at final moment we have potential gravitational energy and potential elastic energy so
, using this on (2)
(3)
Additional if we define the cero of potential gravitational energy as sketched on the figure below (See image attached), and we have by (3) :
(4)
Now when the block 1 moves a distance d upward the block 2 moves downward a distance d too (to maintain a constant length of the rope) and the spring stretches a distance d, so (4) is:
dividing both sides by d
, with k the constant of the spring and g the gravitational acceleration.
Explanation:
Below is an attachment containing the solution.
