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3 years ago

What is the Doppler Effect equation?

1 answer:

7 0

Fperson =[( velocity of wind )+ or - (velocity of person)] / [(velocity of wind) + or - (velocity of sounds)] x frekuency of sounds

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If a boat and its riders have a mass of 1100 kg and the boat drifts in at 1.3 m/s how much work does Sam do to stop it

andriy [413]

Answer:

-929.5Joules

Explanation:

To get the work done by sam, we will calculate the kinetic energy of sam expressed as;

KE = 1/2mv²

m is the mass = 1100kg

v is the velocity = 1.3m/s

KE = 1/2(1100)(1.3)²

KE = 550(1.69)

KE = 929.5Joules

Since Sam is opposing the direction of movement, work done by him will be a negative work i.e -929.5Joules

5 0

3 years ago

Describe the relationship between the length and period of a pendulum in the language of direct proportions

Wittaler [7]

The period of the pendulum is directly proportional to the square root of the length of the pendulum

Explanation:

The period of a simple pendulum is given by the equation

$T=2\pi \sqrt{\frac{L}{g}}$

where

T is the period

L is the length of the pendulum

g is the acceleration of gravity

From the equation, we see that when the length of the pendulum increases, the period of the pendulum increases as the square root of L, $T\propto \sqrt{L}$ . This means that

The period of the pendulum is directly proportional to the square root of the length of the pendulum

From the equation, we also notice that the period of a pendulum does not depend on its mass.

#LearnwithBrainly

3 0

3 years ago

A rocket is attached to a toy car that is confined to move in the x-direction ONLY. At time to = 0 s, the car is not moving but

laiz [17]

Answer:

What displacement must the physics professor give the car

= 12.91 METERS

Explanation:

Check the attached file for explanation

4 0

4 years ago

WHAT STEPS CAN YOU TAKE IF YOU BEEN A VICTIM OF ASSAULT

AfilCa [17]

Answer:

If you have a parental figure or guardian ask them for assistance. Contact a lawyer if you are willing to take action against your attacker.

3 0

3 years ago

In the equilibrium position, the 30-kg cylinder causes a static defl ection of 50 mm in the coiled spring. If the cylinder is de

MArishka [77]

Answer:

2.23 Hz

Explanation:

From the attached diagram below; there exists a diagrammatic representation of the equilibrium position of the cylinder.

The equilibrium position of the spring is expressed as:

mg = K $\delta _{st}$

where;

m = mass of the object

g = acceleration due to gravity

K = spring constant

$\delta _{st}$ = static deflection of the string

Given that:

m = 30 kg

g = 9.81 m/s²

$\delta _{st}$ = 50 mm = 50 × $\frac{1 \ m}{1000 \ m}$

= 0.05 m

Then;

$30 * 9.81= k * 0.05\\k = \frac{30*9.81}{0.05} \\k = 5886 N/m$

From here; let us find the angular velocity which will be needed to determine the natural frequency aftewards.

The angular velocity of the cylinder can be expressed by the formula:

$\omega_{n} = \sqrt{\frac{k}{m}}$

$\omega_{n} = \sqrt{\frac{5886}{30}}$

$\omega_{n} = \sqrt{196.2}$

$\omega_{n} = 14.007141 \ \ rad/s$

Finally; the natural frequency $f_n$ can be calculated by using the equation

$f_n = \frac{\omega_n}{2 \ \pi }$

$f_n = \frac{14.007141}{2 \ \pi }$

$f_n$ = 2.229305729

$f_n$ ≅ 2.23 Hz

Thus; the resulting natural frequency of the vertical vibration of the cylinder = 2.23 Hz

3 0

3 years ago