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VARVARA [1.3K]
3 years ago
14

A car traveling on a flat (unbanked) circular track accelerates uniformly from rest with a tangential acceleration of 1.7 m/s^2.

The car makes it one-quarter of the way around the circle before it skids off the track. From these data, determine the coefficeint of static friction between the car and the track
Physics
1 answer:
Komok [63]3 years ago
5 0

Answer:

The coefficient of static friction between the car and the track

u=0.572

Explanation:

We don't know the mass of the car or any other information so the acceleration is the reason to solve the friction coefficient

∑F=F_{f}=m*a_{t}

As we know

F_{f}=u*F_{N}=u*m*g

Also the center ward direction forces

F_{fc}=m*a_{c}

a_{c}=\frac{v_{t}^2}{r}

F_{fc}=m*\frac{v_{t}^2}{r}

But now vt relation with the tangential acceleration

v_{t}=2*a_{t}*\frac{\pi }{r}

replacing

F_{fc}=m*a_{t}*\frac{2\pi*r}{2r}

F_{fc}=m*a_{t}*\pi

So magnitude of the force can get by

F_{f}=\sqrt{(m*a_{t}*\pi)^{2}+(m*a_{t})^{2}}

Get the factor to simplify

F_{f}=a_{t}*m*\sqrt{(1+\pi^2)}

u*m*g=m*a_{t}*(\sqrt{1+\pi^2})

Solve to u'

u=\frac{a_{t}}{g}*(\sqrt{1+\pi^2})

u=\frac{17\frac{m}{s^2} }{9.8\frac{m}{s^2}}*(\sqrt{1+\pi^2})=0.572

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Andreas93 [3]

Answer:

<em>1.06 atm</em>

Explanation:

On the open end of the tube, the pressure will be the sum of atmospheric pressure and the pressure due to the height of water

The pressure due to a height of water = ρgh

where ρ is the density of water = 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

h is the height of the water column

The height of water column on the open end = 100 cm = 1 m

pressure on this end = ρgh = 1000 x 9.81 x 1 = 9810 Pa

Atmospheric pressure = 101325 Pa

The total pressure on the open end =  101325 Pa + 9810 Pa = <em>111135 Pa</em>

The pressure due to the water column on the closed end = ρgh

The height of the water in the closed end = 40 cm = 0.4 m

The pressure due to this column of water = 1000 x 9.81 x 0.4 = <em>3924 Pa</em>

The resultant pressure on the water on the top of the closed end of the tube = 111135 Pa - 3924 Pa =<em> 107211 Pa</em>

In atm unit, this pressure = 107211/101325 = <em>1.06 atm</em>

7 0
3 years ago
A car traveling at 20 m/s when the driver sees a child standing in the road. He takes 0.80 s to react, then steps on the brakes
mr Goodwill [35]

When driver see the child standing on road his speed is 20 m/s

So here at that instant his reaction time is 0.80 s

He will cover a total distance given by product of speed and time

d_1 = v* t

d_1 = 20 * 0.8

d_1 = 16 m

now after this he will apply brakes with acceleration a = 7 m/s^2

so the distance covered before it stop is given by

v_f^2 - v_i^2 = 2 a d

0 - 20^2 = 2*(-7)*d_2

d_2 = 28.6 m

so the total distance covered by it

d = d_1 + d_2

d = 16 + 28.6 = 44.6 m

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It’s gonna be Oxygen ....
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3 years ago
A. How far does a 100-newton force have to move to do 1,000 joules
Aloiza [94]

Work done by a force is given as the product of force and the distance moved by the force.

<h3>What is work done?</h3>

Work done is the product of force and the distance moved by the the force.

  • Work done = Force × distance

Thus, distance required by the 100 N force is given as:

  • Distance = work done/force

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Distance to be moved is 10 m.

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Work done by the athlete after one push-up = 250 × 0.25 m

Work done by the athlete = 62.5 J

Distance moved by the force = 0 m

Work done = 500 × 0 = 0 N

Therefore, for work to be done, force has to move a distance.

Learn more about work done at: brainly.com/question/25573309

5 0
2 years ago
A certain cloud contains 220 water droplets per cubic centimeter. If 1cubic meter = 1,000,000cubic centimeters, how many drops a
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Wouldn't you just have to multiply 220 by 1,000,000? That would mean there are 220,000,000 water droplets in one cubic of the cloud.
3 0
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