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icang [17]
3 years ago
8

What are the possible effects of global warming?

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0
A possible effect is the risk of Icecaps melted
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hii, just wondering how to solve this? it’s simple scientific notation but my brain just isn’t functioning today so it’s be help
arlik [135]
Honestly just use desmos or mathyway
8 0
3 years ago
If a typical current density (current per unit cross-sectional area) in the cell membrane is 5 mA/cm2 when the voltage across th
Readme [11.4K]

Answer:

<u>note: </u>

<u>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment </u>

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4 0
3 years ago
What is the net force exerted on a 28.8 kg shopping cart that accelerates at a rate of 2.88 m/s^2?​
Mama L [17]

Answer:

<h2>82.94 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 28.8 × 2.88 = 82.944

We have the final answer as

<h3>82.94 N</h3>

Hope this helps you

6 0
3 years ago
A 12 n cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. what force of friction must be ove
jonny [76]

We must remember that the total net force equation at constant velocity is:

<span>F – Ff = 0</span>

of

F - µN = 0

Using Newton's 2nd Law of Motion:<span>

F = m a 

<span>Where,

F = net force acting on the body 
m = mass of the body 
a = acceleration of the body 

Since the cart is moving at a constant velocity, then acceleration is zero, hence the working equation simplifies to 

F = net Force = 0 

Therefore, 

F - µN = 0 

where 

µ = coefficient of friction = 0.20 
N = normal force acting on the cart = 12 N 

Therefore, 

F - 0.20(12) = 0 

<span>F = 2.4 N </span></span></span>
4 0
3 years ago
How is a revolution related to a year
nikdorinn [45]
Revolution means orbiting around another body. 
<span>A year is the time for a planet to complete one orbit around the Sun. 100% sure

</span>
4 0
3 years ago
Read 2 more answers
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