Bill launched a model rocket, and estimated its height h, In feet, after 1 seconds. His results are shown in the table

Mathematics

ChinBrain

3 years ago

Recent credit activity makes up the final 10%.

1 answer:

gizmo_the_mogwai [7]3 years ago

0 1

Answer:

Bill launched a model rocket, and estimated its height h, In feet, after 1 seconds. His results are shown in the table

Time, 1 0 1 2 3 4

Height, h 0 110 190 240 255

Bill's data can be modeled by the function h(t) = -1612 + 128.

Which value is the best prediction for the height of the rocket after 5.5 seconds?

A 150 ft

B. 180 ft

C. 220 ft

D. 250 ft

E 260 ft

ChinBrain

3 years ago

You basically copy and pasted the user's question.

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In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$