Answer:
i think the first is positive if thats what you are looking the other two are negative i think
first one is strong and 2nd one is weak 3rd one is moderate please give brainliest i need 5 to rank up and i only have 1
Answer:
1st and 3rd go in the 1st box
2nd and 4th go in the 2nd box
last one goes in the last box
Step-by-step explanation:
1,2,3,4,5 and time spent jogging go in independent quantity
3.5, 7, 10.5, 14, 17.5 and distance traveled go in dependent quantity
m=3.5h goes in neither
Answer:
V=M/D
Step-by-step explanation:
D=M/V
multiply both sides by V
divide both sides by d
V=M/D
Complete question :
A data set includes data from student evaluations of courses. The summary statistics are nequals92, x overbarequals4.09, sequals0.55. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Answer:
H0 : μ = 4.25
H1 : μ < 4.25
T = - 2.79
Pvalue =0.0026354
we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%
Step-by-step explanation:
Given :
n = 92, xbar = 4.09, s = 0.55 ; μ = 4.25
H0 : μ = 4.25
H1 : μ < 4.25
The test statistic :
T = (xbar - μ) ÷ s / √n
T = (4.09 - 4.25) ÷ 0.55/√92
T = - 0.16 / 0.0573414
T = - 2.79
The Pvalue can be obtained from the test statistic, using the Pvalue calculator
Pvalue : (Z < - 2.79) = 0.0026354
Pvalue < α ; Hence, we reject the Null
Thus, we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%
