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Daniel [21]
3 years ago
12

The field between two charged parallel plates is kept constant. If the two plates are brought closer together, the potential dif

ference between the two plates either a) decrease b) does not change c) increase?
Physics
1 answer:
IRISSAK [1]3 years ago
7 0

Since the electric field between the plates is constant

so we can say the relation between potential difference and electric field is given by

\Delta V = E. d

here from above relation we can say that is electric field is kept constant then potential difference is directly proportional to the distance between the plates

so here we will say that if the distance between the plates is decreased then the potential difference between the plates will also decreases

So correct answer will be

<u>a) decrease </u>

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Answer:

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Explanation:

This problem is an exercise of movement in two dimensions, the best way to solve it is to decompose the terms and work each axis independently.

Break down the speeds in two moments

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  v₀ₓ = v₀ cos θ

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v_{oy} = 3.05 m / s

Final

vₓ = 6.03 cos (-56.7)

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v_{y} = 6.03 sin (-56.7)

v_{y} = -5.04 m / s

Having the speeds and the time, we can use the definition of average acceleration that is the change of speed in the time order

    a = (v_{f} - v₀) /t

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   a_{y} =  -2.697 m/s²

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