<u>Answer:</u> The half life of the reaction is 593.8 seconds
<u>Explanation:</u>
We are given:
Rate constant =
The formula for determining the unit of 'k' is:
where, n = order of reaction
The unit of concentration is, M or mole/L
The unit of time is, second or 's'
Evaluating the value of 'n' from above equation:
The reaction is zero order reaction.
The equation used to calculate half life for zero order kinetics:
where,
k = Rate constant =
= initial concentration = 1.90 mol/L
Putting values in above equation, we get:
Hence, the half life of the reaction is 593.8 seconds
Divide the error by the exact or ideal value (i.e., not your experimental or measured value). This will give you a decimal number. Convert the decimal number into a percentage by multiplying it by 100. Add a percent or % symbol to report your percent error value.
The ether that is formed when ethyl alcohol is heated in the presence of sulfuric acid that is concentrated is called diethyl ether. Heating the alcohol breaks the bond between the R group and the OH group forming an ether. The formula of the ether would be CH3CH2OCH2CH3.
Answer:
1.28 mol Cu(OH)₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
125 g Cu(OH)₂
<u>Step 2: Identify Conversions</u>
Molar Mass of Cu - 63.55 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of Cu(OH)₂ - 63.55 + 2(16.00) + 2(1.01) = 97.57 g/mol
<u>Step 3: Convert</u>
= 1.28113 mol Cu(OH)₂
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
1.28113 mol Cu(OH)₂ ≈ 1.28 mol Cu(OH)₂