Answer:
The melting point of this substance at 1 ATM of pressure is 110°.
In carbohydrates the C:H:O is 1:2:1
For the answer to the question above, since the process is carried out at constant pressure,
<span>work = P (V1-V2) </span>
<span>= 1.3 E5 (6-12) = -7.8 E5 N.m (in this case the work is made by the system, so it is negative if work made on the system then it should be positive)</span>
