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4 years ago

Astronomy can best be described as a/an

2 answers:

7 0

As·tron·o·my- the branch of science that deals with celestial objects, space, and the physical universe as a whole. That's the definition hope it is what you need and that it helps:)

True [87]4 years ago

5 0

The study of heavenly bodies.

How that differs from astrophysics, astro dynamics, cosmology, etc., I'm not entirely sure.

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What is a satellite?

Bumek [7]

Answer:

Explanation:

answer is c I hope it is correct

8 0

3 years ago

A sinusoidal electromagnetic wave is propagating in a vacuum in the +z-direction.Part AIf at a particular instant and at a certa

stira [4]

Explanation:

Given that,

Magnitude of electric field in +x direction, E = 4.9 V/m

Part A :

The relation between electric and magnetic field is given by :

$B=\dfrac{E}{c}$

c is the speed of light

$B=\dfrac{4.9\ V/m}{3\times 10^8\ m/s}$

$B=1.63\times 10^{-8}\ T$

So, the magnetic field of the wave at this same point in space and instant in time is $1.63\times 10^{-8}\ T$ .\

Part B :

The direction of electric and magnetic field is same i.e. +x direction.

Hence, this is the required solution.

8 0

4 years ago

A uniformly charged rod (length = 2.0 m, charge per unit length = 5.0 nc/m) is bent to form one quadrant of a circle. what is th

Neko [114]

Electric field at the center of circular arc is given by the formula

$E = \frac{2k\lambda sin\frac{\theta}{2}}{R}$

here we know that

$\lambda = 5nC/m$

$k = 9 \times 10^9 Nm^2/C^2$

$\frac{\pi}{2}R = L = 2m$

$R = \frac{4}{\pi}$

also we know that

$\theta = \frac{\pi}{2}$

now from above formula

$E = \frac{2(9\times 10^{-9})(5\times 10^{-9})sin45}{4/\pi}$

$E = 50 N/C$

4 0

3 years ago

(Really Need Help!) (55 points) (4 Choices) Which of the following is not a true statement?

Lena [83]

The last one, at the bottom, is false.

6 0

4 years ago

A car has a mass of 1200 kg. A man can comfortably push down with a force of 400 N. If the small piston in a hydraulic jack has

kotegsom [21]

A) F1/A1=F2/A2
F2 = 12000 Newtons, while F1 = 400 Newtons and area A1= 6 cm²
400/6 = 12000/A2
A2 = (6 × 12000)/400
= 180 cm²

b) How long does this lift the car
d2 =F1/F2×d1
= (400/12000)× 20
= (1/30)×20
= 20/30
= 0.67 cm
This lifts the car a distance of 0.67 cm

4 0

3 years ago