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Aloiza [94]
3 years ago
9

In extremely large​ forests, it is not​ cost-effective to position forest rangers in towers or to use small aircraft to continua

lly watch for fires. Since lightning is a frequent cause of​ fire, lightning detectors are now commonly used instead. These devices not only give a bearing on the location but also measure the intensity of the lightning. A detector at point Q is situated 11 miles west of a central fire station at point R. The bearing from Q to where lightning hits due south of R is S37.3​°E. How far is the hit from point​ R?

Physics
1 answer:
Sati [7]3 years ago
3 0

Answer:

Point R is at 14.28 miles.

Explanation:

According to the attached image:

Q = 90 - 37.6 = 52.4°

Using the tangent property:

tanθ = s/11

s = 11 * tanθ = 11 * tan52.4 = 14.28 miles

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A group of students conduct an experiment with a block of wood sliding down an incline. They find that the final energy of the b
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1) 51 m

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2 years ago
Describe how a planet, solar system, galaxy, and the universe are related in terms of size.
Alexus [3.1K]

- The Solar System contains the sun and objects that orbit it, including the eight planets, comets, and asteroids, and the Galaxy contains about 100 billion stars, of which the sun is one, as well as large clouds of gas and dust. - The universe contains all physical matter and energy

So Therefore Universe Is the biggest terms of size because it contains all physical matter and energy hope it helps

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2 years ago
True or false 6.02x10^23 atoms of oxygen have a mass of 16g ?
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True

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5 0
3 years ago
Filtration is used to separate mixtures based on _____.
sergejj [24]
Based on particle size.
its where a solid is separated from a liquid. filter paper has tiny holes only allowing small molecules to pass
8 0
2 years ago
Read 2 more answers
Please help me guys never mind the calculations ​
vlada-n [284]

The shape is connected in parallel so;

5.1) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{2}  +  \frac{1}{3}  \\  \frac{1}{R}  =  \frac{3 + 2}{6}  =  \frac{5}{6}  \\ R =  \frac{6}{5}  = 1.2 \:  \: ohm

5.2) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{8}  +  \frac{1}{10}  \\  \frac{1}{R}  =  \frac{5 + 4}{40}  =  \frac{9}{40}  \\ R =  \frac{40}{9}  = 4.4 \:  \: ohm

I hope I helped you^_^

7 0
2 years ago
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