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4 years ago

The mass number of a nucleus (except Hydrogen) is:

2 answers:

7 0

The mass number of a nucleus (except Hydrogen) is: number of protons + number of neutrons.

A=Z+N

A=mass number=protons + neutrons.
Z=atomic number=number of protons.
N=number of neutrons.

In the case of Hydrogen it depends of isotope of Hydrogen .
the hydrogen has three isotopes,
protium : A=Z, because N=0
deuterium: A=Z+N; N=1
tritium: A=Z+N; N=2

Harlamova29_29 [7]4 years ago

6 0

Answer:

never less than its atomic number.

Explanation:

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12) A horizontal force of 200 N is applied to move a 55-kg cart (initially at rest) across a 10 m level surface. What is the fin

WINSTONCH [101]

Hi there!

We can use the following:

W = ΔKE = F · d

Find the work done on the cart:

W = 200 · 10 = 2000 J

Now, this is equal to the change in kinetic energy of the object. Its initial kinetic energy is 0 J since it starts from rest, so:

2000J = KEf - KEi

KE is given as:

$KE = \frac{1}{2}mv^2$

2000J = 1/2(55)v²

4000 = 55v²

√(4000/55) = 8.53 m/s

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3 years ago

What is 52,427 in scientific notation?

Shkiper50 [21]

Answer: Why is 52,427 written as 5.2427 x 104 in scientific notation

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4 years ago

If the magnetic field is held constant at 3.0 T and the loop is pulled out of the region that contains the field in 0.2 s, what

kap26 [50]

Answer:

emf = 15 * Area and if A is given in square meters, the units of the emf will be Volts

Explanation:

Assuming that the area of the loop of current (A) is known, the magnitude of the induced emf can be calculated using Faraday-Lenz's Law:

$emf=|-\frac{\Delta\,\Phi}{\Delta \,t} |=|\frac{A\,B}{\Delta \,t}|=|\frac{A\,(3)}{0.2}|=15\,A$

and if the area (A) is given in square meters, the emf will directly come in units of Volts.

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4 years ago

What is the net force on the purple ring in the picture above. _________

Dmitrij [34]

Answer:

equal

Explanation:

Because of Newton's third law

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3 years ago

A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occ

Neporo4naja [7]

Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
$F=ma$
Using $m=65 kg$ and $a=5 m/s^2$ , we can find the value of the force applied to the roller-blade to obtain this acceleration:
$F=(65 kg)(5 m/s^2)=325 N$

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3 years ago