3 years ago

Given the arithmetic sequence an = 2 − 5(n + 1), what is the domain for n?

1 answer:

4 0

The correct answer among all the other choices is "All real numbers." Given the arithmetic sequence an = 2 − 5(n + 1), the domain for n could be all real numbers. <span>Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. </span>

You might be interested in

Which scatterplot does NOT suggest a linear relationship between x and y. Look AT IMAGE

Afina-wow [57]

Answer:

Graph C

Step-by-step explanation:

It is Graph C because the points are majorly curved, while the rest of the lines are linear because they are straight.

Hope this helps! :D

- Luna

7 0

3 years ago

Solve for x: 5x/7 - 5 = 50

katrin [286]

The answer is x =77 hope i help you

7 0

3 years ago

Write the explicit formula for the geometric sequence.<br><br> a1 = -5 a2 = 20 a3 = -80

Anni [7]

$a_1 = -5;\ a_2 = 20;\ a_3 = -80 \\\\a_2:a_1=r\ and\ a_3:a_2=r\\\\r=20:(-5)=-4\ check\ r=-80:20=-4\\\\a_n=a_1r^{n-1}\to a_n=-5\cdot(-4)^{n-1}=-5\cdot(-4)^{-1}\cdot(-4)^n\\\\=-5\cdot\left(-\dfrac{1}{4}\right)\cdot(-4)^n=\dfrac{5}{4}\cdot(-4)^n\\\\Answer:\boxed{a_n=-5\cdot(-4)^{n-1}\ other\ a_n=\frac{5}{4}\cdot(-4)^n}$

6 0

3 years ago

Find the solution of the differential equation that satisfies the given initial condition. dy/dx = xe^y, y(0) = 0

Anna [14]

$\dfrac{\mathrm dy}{\mathrm dx}=xe^y$
$e^{-y}\,\mathrm dy=x\,\mathrm dx$
$-e^{-y}=\dfrac{x^2}2+C$

$y(0)=0$
$\implies-1=C$
$\implies -e^{-y}=\dfrac{x^2}2-1$
$e^{-y}=1-\dfrac{x^2}2$
$-y=\ln\left(1-\dfrac{x^2}2\right)$
$y=-\ln\left(1-\dfrac{x^2}2\right)$

3 0

3 years ago

Find the function value, f(4) if f(x) = 12x - 1

Scrat [10]

Answer:

f(4) = 47

Step-by-step explanation:

f(x) = 12x - 1

Let x = 4

f(4) = 12(4) -1

= 48 -1

= 47

4 0

4 years ago

Read 2 more answers