Answer:
Mn is the oxidizing agent.
N is the reducing agent.
Explanation:
Hello!
In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:
Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.
Best regards!
We need
the choices to pick from
Explanation:
34.2g of C12H22O11 is dissolved in 180g of H20.
Molar mass of sucrose = 342g/mol
Moles of sucrose = 342 / 34.2 = 10 mol.
Molar mass of water = 18g/mol
Moles of water = 180 / 18 = 10 mol.
For hydrogen atoms, there are 22 * 10 in sucrose and 2 * 10 in water, which gives a total of 240.
For oxygen atoms, there are 11 * 10 in sucrose and 1 * 10 in water, which gives a total of 120.
Gasoline will not dissolve in water because gasoline has more density then the water
Answer:
Explanation:
Hello,
In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior via a directly proportional relationship:
Thus, since we are asked to compute the final pressure we solve for it in the previous formula, considering the temperature in absolute Kelvin units:
Best regards.
